Question

С2H5COONa→C2H5COOH→C2H5COOK→(C2H5COO)2Ca

Answer 1

С2H5COONa + HCl = NaCl + C2H5COOH

C2H5COOH + KOH = C2H5COOK + H2O

2C2H5COOK + CaCl2 = 2KCl + (C2H5COO)2Ca

Answer 2

The reaction you have provided involves a series of transformations starting with the compound sodium ethanoate (C2H5COONa) and ending with the compound calcium diethanoate ((C2H5COO)2Ca). Let's go through each step of the reaction sequence:

1. C2H5COONa (sodium ethanoate) → C2H5COOH (ethanoic acid): In this step, sodium ethanoate (also known as sodium acetate) is converted to ethanoic acid (also known as acetic acid) by the addition of a strong acid, such as hydrochloric acid (HCl). The reaction can be represented as follows: C2H5COONa + HCl → C2H5COOH + NaCl

2. C2H5COOH (ethanoic acid) → C2H5COOK (potassium ethanoate): To convert ethanoic acid to potassium ethanoate, you would react it with a base, such as potassium hydroxide (KOH). This reaction is an acid-base reaction and is represented as follows: C2H5COOH + KOH → C2H5COOK + H2O

3. C2H5COOK (potassium ethanoate) → (C2H5COO)2Ca (calcium diethanoate): Finally, to obtain calcium diethanoate, you would react potassium ethanoate with a calcium salt, such as calcium chloride (CaCl2). The reaction can be written as follows: 2 C2H5COOK + CaCl2 → (C2H5COO)2Ca + 2 KCl

Overall, the complete reaction sequence can be summarized as: C2H5COONa + HCl → C2H5COOH + NaCl C2H5COOH + KOH → C2H5COOK + H2O 2 C2H5COOK + CaCl2 → (C2H5COO)2Ca + 2 KCl

Please note that the reaction conditions and specific reagents may vary depending on the actual experimental setup or intended purpose of the reaction.