Question

Розчин сульфатної кислоти масою 98 г із масовою часткою кислоти 10 % повністю нейтралізували калій гідроксидом. Обчислити масу утвореної солі.​

Answer 1

Маса сульфатної кислоти (H2SO4) у розчині:
Маса сульфатної кислоти = Маса розчину × Масова частка H2SO4
Маса сульфатної кислоти = 98 г × 10% = 9.8 г

Знаючи, що калій гідроксид (KOH) нейтралізує кожен моль H2SO4 з формулою H2SO4 + 2KOH -> K2SO4 + 2H2O, ми можемо визначити, як моль H2SO4 перейде в масу солі (K2SO4).
Маса солі (K2SO4) = Маса H2SO4 (у моль) × Маса K2SO4 (у г/моль)

Знаючи масу H2SO4 (9.8 г) і масу молекулярну масу K2SO4, яка дорівнює 174.26 г/моль (2 * 39.1 г/моль за K + 32.07 г/моль за S + 4 * 16.00 г/моль за O), ми можемо знайти масу солі:

Маса солі (K2SO4) = (9.8 г / 98.08 г/моль H2SO4) * 174.26 г/моль K2SO4 ≈ 17.35 г

Отже, маса утвореної солі (K2SO4) становить приблизно 17.35 г.

Answer 2

Calculation of the mass of the formed salt

To calculate the mass of the formed salt, we need to determine the amount of potassium hydroxide (KOH) required to neutralize the sulfuric acid (H2SO4).

Given: - Mass of sulfuric acid (H2SO4) = 98 g - Mass fraction of acid in sulfuric acid = 10%

To neutralize the acid, we can use the balanced chemical equation for the reaction between sulfuric acid and potassium hydroxide:

H2SO4 + 2KOH -> K2SO4 + 2H2O

From the equation, we can see that 1 mole of sulfuric acid reacts with 2 moles of potassium hydroxide to form 1 mole of potassium sulfate.

To find the moles of sulfuric acid, we can use the formula:

moles = mass / molar mass

The molar mass of sulfuric acid (H2SO4) is: (2 * atomic mass of hydrogen) + atomic mass of sulfur + (4 * atomic mass of oxygen)

Now we can calculate the moles of sulfuric acid:

moles of H2SO4 = 98 g / (2 * atomic mass of hydrogen + atomic mass of sulfur + 4 * atomic mass of oxygen)

Next, we need to determine the moles of potassium hydroxide required to neutralize the sulfuric acid. Since the reaction is 1:2 between sulfuric acid and potassium hydroxide, the moles of KOH will be half of the moles of H2SO4.

moles of KOH = (1/2) * moles of H2SO4

Finally, we can calculate the mass of the formed salt (potassium sulfate, K2SO4) using the moles of KOH:

mass of K2SO4 = moles of KOH * molar mass of K2SO4

Please note that the atomic masses of hydrogen, sulfur, oxygen, and potassium can be found in the periodic table.

Let's calculate the mass of the formed salt:

1. Calculate the molar mass of sulfuric acid (H2SO4): - Atomic mass of hydrogen (H) = 1 g/mol - Atomic mass of sulfur (S) = 32.07 g/mol - Atomic mass of oxygen (O) = 16 g/mol - Molar mass of H2SO4 = (2 * 1) + 32.07 + (4 * 16) = 98.09 g/mol

2. Calculate the moles of sulfuric acid (H2SO4): - Moles of H2SO4 = 98 g / 98.09 g/mol = 1 mol

3. Calculate the moles of potassium hydroxide (KOH): - Moles of KOH = (1/2) * 1 mol = 0.5 mol

4. Calculate the molar mass of potassium sulfate (K2SO4): - Atomic mass of potassium (K) = 39.1 g/mol - Atomic mass of sulfur (S) = 32.07 g/mol - Atomic mass of oxygen (O) = 16 g/mol - Molar mass of K2SO4 = (2 * 39.1) + 32.07 + (4 * 16) = 174.27 g/mol

5. Calculate the mass of the formed salt (K2SO4): - Mass of K2SO4 = 0.5 mol * 174.27 g/mol = 87.14 g

Therefore, the mass of the formed salt (potassium sulfate) is 87.14 grams.

Note: The provided search results did not contain relevant information for this specific calculation. The calculation is based on the stoichiometry of the reaction between sulfuric acid and potassium hydroxide.