Question

Al2O3→Al3(SO4)3→Al(OH)3→Al2O3

Answer 1

Ответ:

1)4Al+3O2=2Al2O3

2)Al2O3+3H2SO4=Al2(SO4)3+3H2O

3)2Al(OH)3=Al2O3+3H2O

вроде вот так)

Answer 2

Al2O3 + 3H2SO4 = Al2(SO4)3 + 3H2O

Al2(SO4)3 + 6NaOH = 2Al(OH)3↓ + 3Na2SO4

2Al(OH)3 = Al2O3 + 3H2O

Answer 3

The chemical reactions you provided seem to describe a cyclic process involving aluminum oxide (Al2O3) and its conversion into other compounds. However, the reactions are not balanced, and some parts seem incorrect. I'll attempt to correct and balance the reactions for you:

1. Aluminum oxide (Al2O3) reacting with sulfuric acid (H2SO4) to form aluminum sulfate (Al2(SO4)3) and water (H2O): Balanced equation: Al2O3 + 3 H2SO4 → Al2(SO4)3 + 3 H2O

2. Aluminum sulfate (Al2(SO4)3) reacting with water (H2O) to form aluminum hydroxide (Al(OH)3) and sulfuric acid (H2SO4): Balanced equation: Al2(SO4)3 + 6 H2O → 2 Al(OH)3 + 3 H2SO4

3. Aluminum hydroxide (Al(OH)3) dehydrating to form aluminum oxide (Al2O3) and water (H2O): Balanced equation: 2 Al(OH)3 → Al2O3 + 3 H2O

The overall process can be summarized as:

Al2O3 + 3 H2SO4 → Al2(SO4)3 + 3 H2O Al2(SO4)3 + 6 H2O → 2 Al(OH)3 + 3 H2SO4 2 Al(OH)3 → Al2O3 + 3 H2O

These reactions show a cyclic process where aluminum oxide is converted to aluminum sulfate, then to aluminum hydroxide, and finally, back to aluminum oxide.