Question

CH3-CH2-CH=CH2+HBr-->​

Answer 1

Ответ:

СН3-СН2-СН(Br)-СН3

Объяснение: даны ли там какие-либо условия реакции?

Answer 2

The reaction you've described is an example of an addition reaction involving an alkene and a hydrogen halide. In this case, the alkene is 1-butene (CH3-CH2-CH=CH2) and the hydrogen halide is hydrogen bromide (HBr).

The reaction proceeds as follows:

CH3-CH2-CH=CH2 + HBr → CH3-CH2-CH2-CH2Br

In this reaction, the π (pi) bond in the alkene is broken, and the hydrogen and bromine atoms are added to the carbon atoms that were part of the double bond. As a result, the double bond is converted into a single bond, and a new carbon-bromine (C-Br) bond is formed.

The product of the reaction is 1-bromobutane (CH3-CH2-CH2-CH2Br), which is an alkyl bromide. Alkyl bromides are useful intermediates in various chemical processes and can be further functionalized for the synthesis of more complex compounds.