Question

Cu → cuo → cuso4 → cu(oh)2

Answer 1

Объяснение:

2Cu+O2=2CuO

CuO+H2SO4=CuSO4+H2O

CuSO4+2NaOH=Cu(OH)2+Na2SO4

Answer 2

The sequence you've mentioned represents the oxidation and hydrolysis reactions of copper (Cu). Let's break it down step by step:

1. Cu → CuO: In this step, copper (Cu) undergoes oxidation to form copper(II) oxide (CuO). The copper atom loses two electrons to become copper(II) ions (Cu²⁺), which then combine with oxygen (O) to form CuO. The reaction can be represented as: 2Cu + O₂ → 2CuO

2. CuO → CuSO₄: In the next step, copper(II) oxide (CuO) reacts with sulfuric acid (H₂SO₄) to produce copper(II) sulfate (CuSO₄) and water (H₂O). The reaction can be represented as: CuO + H₂SO₄ → CuSO₄ + H₂O

3. CuSO₄ → Cu(OH)₂: In this final step, copper(II) sulfate (CuSO₄) reacts with sodium hydroxide (NaOH) to yield copper(II) hydroxide (Cu(OH)₂) and sodium sulfate (Na₂SO₄). The reaction can be represented as: CuSO₄ + 2NaOH → Cu(OH)₂ + Na₂SO₄

Overall, the complete sequence is: Cu → CuO → CuSO₄ → Cu(OH)₂