Question

Fe+CuSO4=Zn+CuSO4=FeSO4+NaOH=H2SO4+BaCl2=BaCl2+AgNO3=​

Answer 1

Ответ:

Объяснение:

Fe+CuSO₄= FeSO₄+Cu

Zn+CuSO₄= ZnSO₄+Cu

FeSO₄+2NaOH= Fe(OH)₂↓+Na₂SO₄

H₂SO₄+BaCl₂= BaSO₄↓+2HCI

BaCl₂+2AgNO₃=​2AgCI↓+Ba(NO₃)₂

Answer 2

It looks like you've provided a series of chemical reactions involving various elements and compounds. Let's analyze each one:

1. Fe + CuSO4 = ? This equation appears to represent the reaction between iron (Fe) and copper sulfate (CuSO4). This is a single displacement or single replacement reaction, where iron displaces copper in the compound. The balanced chemical equation for this reaction is: Fe + CuSO4 → FeSO4 + Cu

2. Zn + CuSO4 = ? This equation represents the reaction between zinc (Zn) and copper sulfate (CuSO4). Similar to the previous reaction, this is also a single displacement reaction, with zinc displacing copper in the compound. The balanced equation is: Zn + CuSO4 → ZnSO4 + Cu

3. FeSO4 + NaOH = ? This equation seems to represent the reaction between ferrous sulfate (FeSO4) and sodium hydroxide (NaOH). This is a double displacement reaction, leading to the formation of iron hydroxide (Fe(OH)2) and sodium sulfate (Na2SO4). The balanced equation is: FeSO4 + 2 NaOH → Fe(OH)2 + Na2SO4

4. H2SO4 + BaCl2 = ? This equation represents the reaction between sulfuric acid (H2SO4) and barium chloride (BaCl2). This is a double displacement reaction, leading to the formation of barium sulfate (BaSO4) and hydrochloric acid (HCl). The balanced equation is: H2SO4 + BaCl2 → BaSO4 + 2 HCl

5. BaCl2 + AgNO3 = ? This equation represents the reaction between barium chloride (BaCl2) and silver nitrate (AgNO3). This is a double displacement reaction, leading to the formation of barium nitrate (Ba(NO3)2) and silver chloride (AgCl), which is a solid precipitate. The balanced equation is: BaCl2 + 2 AgNO3 → 2 AgCl + Ba(NO3)2

It's important to note that chemical reactions need to be balanced to accurately represent the conservation of matter. If you have specific quantities or conditions for these reactions, please provide them, and I can help with more detailed calculations.