Question

Calculate the mole number in 57.6 g of Ti2O3. (Ti=48, O=16) 3.     What is the mole number of 196 g Cr2(SO4)3? (Cr=52, S=32, O=16)4.     1.5 mol of compound Mg3X2 has mass 150 g. What is the atomic mass of element X? (Mg=24)5.     0.15 mol of compound Ca3(XO4)2 has mass 59.7 g. What is the atomic mass of element X in the compound? (Ca=40, O=16) срочно нужно!!!!!!!!​

Answer 1

Ответ:

1) you have to divide the weight of Ti2O3 in its molar mass

So, the weight is 57,6 g, and the molar mass is: 48×2+16×3=96+48=144

57,6:144=0,4

The answer: the mole number in 57,6 g of Ti2O3 is 0,4.

2)Cr2(SO4)3=52×2+((32+16×4)×3)=392

196:392=0,5

The answer: The Mole number of 196 g Cr2(SO4) 3 is 0,5

3)

$\frac{150}{x} = \frac{15}{10}$

15/10 is 1,5,just in other type

So:

15x=1500

x=100

We found that the molar mass of Mg3X2 is 100

We know that the atomic mass of Mg is 24

So,24×3=72

100-72=28

28:2=14

So,the atomic mass of X element is 14.

4)

$\frac{59.7}{x} = \frac{15}{100}$

15/100 is 0,15

15x=5970

x=5970/15

x=398

40×3+(16×4)×2=120+128=248

398-248=150

150:2=75

The atomic mass of X is 75

Good luck!

Answer 2

Sure, let's go through each of these calculations step by step:

1. Mole number in 57.6 g of Ti2O3 (Ti=48, O=16):

   The molecular formula of titanium (III) oxide (Ti2O3) indicates that there are 2 atoms of titanium (Ti) and 3 atoms of oxygen (O) in each molecule.

   The molar mass of Ti2O3 = (2 * Ti atomic mass) + (3 * O atomic mass) Molar mass of Ti2O3 = (2 * 48) + (3 * 16) = 96 + 48 = 144 g/mol

   Number of moles = Given mass / Molar mass Number of moles = 57.6 g / 144 g/mol ≈ 0.4 moles

2. Mole number of 196 g Cr2(SO4)3 (Cr=52, S=32, O=16):

   The molecular formula of chromium (III) sulfate (Cr2(SO4)3) indicates that there are 2 atoms of chromium (Cr), 3 atoms of sulfur (S), and 12 atoms of oxygen (O) in each molecule.

   The molar mass of Cr2(SO4)3 = (2 * Cr atomic mass) + (3 * S atomic mass) + (12 * O atomic mass) Molar mass of Cr2(SO4)3 = (2 * 52) + (3 * 32) + (12 * 16) = 104 + 96 + 192 = 392 g/mol

   Number of moles = Given mass / Molar mass Number of moles = 196 g / 392 g/mol = 0.5 moles

3. Atomic mass of element X in compound Mg3X2 (Mg=24):

   You are given that 1.5 mol of Mg3X2 has a mass of 150 g. Since Mg has a molar mass of 24 g/mol, you can calculate the molar mass of Mg3X2:

   Molar mass of Mg3X2 = Total mass / Number of moles Molar mass of Mg3X2 = 150 g / 1.5 mol = 100 g/mol

   The molar mass of Mg3X2 is the sum of the molar masses of 3 Mg atoms and 2 X atoms:

   100 g/mol = (3 * 24 g/mol) + (2 * X g/mol) X g/mol = 100 g/mol - 3 * 24 g/mol = 28 g/mol

   So, the atomic mass of element X is 28 g/mol.

4. Atomic mass of element X in compound Ca3(XO4)2 (Ca=40, O=16):

   You are given that 0.15 mol of Ca3(XO4)2 has a mass of 59.7 g. The molar mass of Ca3(XO4)2 is calculated as follows:

   Molar mass of Ca3(XO4)2 = Total mass / Number of moles Molar mass of Ca3(XO4)2 = 59.7 g / 0.15 mol = 398 g/mol

   The molar mass of Ca3(XO4)2 is the sum of the molar masses of 3 Ca atoms, 2 X atoms, and 2 * 4 O atoms:

   398 g/mol = (3 * 40 g/mol) + (2 * X g/mol) + (8 * 16 g/mol) X g/mol = 398 g/mol - (3 * 40 g/mol) - (8 * 16 g/mol) = 62 g/mol

   So, the atomic mass of element X in the compound is 62 g/mol.