Question

SO2+KMnO4+KOH=K2SO4+K2MnO4+H2O​

Answer 1

Ответ:

Объяснение:

SO2+2KMnO4+4KOH=K2SO4+2K2MnO4+2H2O

Это окислительно-восстановительная (редокс) реакция:

2 Mn(VII) + 2 e- → 2 Mn(VI) (восстановления)

SI(V) - 2 e- → S(VI) (окисление)

KMnO4 является окислителем, SO2 является восстановителем.

Answer 2

The given chemical equation represents a redox reaction between sulfur dioxide (SO2), potassium permanganate (KMnO4), and potassium hydroxide (KOH). The reaction produces potassium sulfate (K2SO4), potassium manganate (K2MnO4), and water (H2O).

The balanced chemical equation for the reaction is as follows:

3SO2 + 2KMnO4 + 2KOH → K2SO4 + 2K2MnO4 + 3H2O

In this equation, three molecules of sulfur dioxide (SO2) react with two molecules of potassium permanganate (KMnO4) and two molecules of potassium hydroxide (KOH) to yield one molecule of potassium sulfate (K2SO4), two molecules of potassium manganate (K2MnO4), and three molecules of water (H2O).

It's important to note that this is a balanced equation, indicating that the number of atoms of each element is the same on both sides of the equation.