Question

Al+NaOH+H2O--->?Al2O3+NaOH--->?Al(OH)3+H2SO4--->?Al(OH)3+NaOH--->?​

Answer 1

Объяснение:

2Al + 2NaOH + 6H2O =2 NaAl(OH)4 + 3H2

Al2O3 + 2NaOH = 2NaAlO2 + H2O

2Al(OH)3 + 3H2SO4 = Al2(SO4)3 + 6H2O

Al(OH)3 + NaOH = NaAl(OH)4

Answer 2

Let's break down each step of the chemical reactions you provided:

1. Al + NaOH + H2O → ? This reaction involves aluminum (Al) reacting with sodium hydroxide (NaOH) and water (H2O). It likely produces aluminum hydroxide and hydrogen gas:

   2Al + 6NaOH + 6H2O → 2Al(OH)3 + 3H2

2. Al2O3 + NaOH → ? In this reaction, aluminum oxide (Al2O3) reacts with sodium hydroxide (NaOH) to form sodium aluminate (NaAlO2):

   Al2O3 + 2NaOH → 2NaAlO2

3. Al(OH)3 + H2SO4 → ? When aluminum hydroxide (Al(OH)3) reacts with sulfuric acid (H2SO4), it forms aluminum sulfate (Al2(SO4)3) and water (H2O):

   2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O

4. Al(OH)3 + NaOH → ? This reaction involves aluminum hydroxide (Al(OH)3) reacting with sodium hydroxide (NaOH) to form sodium aluminate (NaAlO2):

   Al(OH)3 + NaOH → NaAlO2 + 2H2O

So, the series of reactions you've provided result in the formation of sodium aluminate (NaAlO2), aluminum sulfate (Al2(SO4)3), and hydrogen gas (H2).