Question

A) NaCl + C12 - HC1 - Agci1)2)3)B) Naci-C12-HCIC12-FeCl3​

Answer 1

Вот решение цепочки реакций

Answer 2

It appears that you've provided chemical reactions involving various compounds. Let's break down and explain each of the reactions:

A)

1. NaCl (Sodium Chloride) reacts with Cl2 (Chlorine gas):

   • NaCl + Cl2 -> No reaction occurs because Cl2 is a diatomic molecule and does not readily react with sodium chloride.

2. HC1 (Hydrochloric Acid) reacts with NaCl:

   • HC1 + NaCl -> NaCl dissolves in hydrochloric acid to form an aqueous solution of sodium chloride (NaCl (aq)).

3. AgCl (Silver Chloride) forms when Ag+ ions are added to the solution:

   • Ag+ ions in solution can react with Cl- ions from the hydrochloric acid to form a white precipitate of AgCl: Ag+ (aq) + Cl- (aq) -> AgCl (s)

So, the final products are NaCl (aq) and AgCl (s).

B)

1. NaCl (Sodium Chloride) reacts with Cl2 (Chlorine gas):

   • NaCl + Cl2 -> No reaction occurs because Cl2 is a diatomic molecule and does not readily react with sodium chloride.

2. HC1 (Hydrochloric Acid) reacts with NaCl:

   • HC1 + NaCl -> NaCl dissolves in hydrochloric acid to form an aqueous solution of sodium chloride (NaCl (aq)).

3. FeCl3 (Iron(III) Chloride) reacts with NaCl:

   • FeCl3 + NaCl -> No reaction occurs because FeCl3 is a stronger Lewis acid compared to NaCl, and the chloride ions (Cl-) will not displace them from FeCl3.

So, the final product is NaCl (aq) in this case.

In both scenarios, the sodium chloride (NaCl) dissolves in hydrochloric acid to form an aqueous solution, but there are no significant reactions with chlorine gas (Cl2) or iron(III) chloride (FeCl3) under the given conditions.