Question

M(CaCO3)=50г.n(Ca CO3)-?,V(CaCO3)-?,N(CaCO3)-?

Answer 1

Ответ:

0, 1530 г.

Объяснение:

n(Mg) = 5:24 г/моль = 0,2 моль (5 баллов) ... 1 ) CaCO3+2 HCI = CaCl2 + CO2 + HO (5 баллов). HCl в ... n(HCl)=C(NaOH) V(NaOH) ... m(CaCO3) = 0,00153 моль : 100 г/моль = 0, 1530 г.

Answer 2

It seems like you're looking to find the molar mass (M), number of moles (n), and volume (V) of a sample of calcium carbonate (CaCO3) with a mass of 50 grams (g). To do this, we'll use the molar mass of calcium carbonate to calculate the number of moles and then determine the volume.

1. Molar Mass (M) of CaCO3: The molar mass of CaCO3 can be calculated by adding the atomic masses of its constituent elements:

• Calcium (Ca) has an atomic mass of approximately 40.08 g/mol.
• Carbon (C) has an atomic mass of approximately 12.01 g/mol.
• Oxygen (O) has an atomic mass of approximately 16.00 g/mol.

Now, calculate the molar mass of CaCO3:

M(CaCO3) = (1 × M(Ca)) + (1 × M(C)) + (3 × M(O)) M(CaCO3) = (1 × 40.08 g/mol) + (1 × 12.01 g/mol) + (3 × 16.00 g/mol) M(CaCO3) = 40.08 g/mol + 12.01 g/mol + 48.00 g/mol M(CaCO3) = 100.09 g/mol

So, the molar mass of CaCO3 is approximately 100.09 g/mol.

2. Number of Moles (n) of CaCO3: Now that we have the molar mass, we can calculate the number of moles using the formula:

n = Mass (g) / Molar Mass (g/mol)

n(CaCO3) = 50 g / 100.09 g/mol n(CaCO3) ≈ 0.499 moles

So, there are approximately 0.499 moles of CaCO3 in the 50-gram sample.

3. Volume (V) of CaCO3: To determine the volume of CaCO3, we need to know the density of the substance. The density of CaCO3 can vary depending on its form (solid, powder, etc.). Once you have the density, you can use the formula:

Volume (V) = Mass (g) / Density (g/cm³)

You'll need to provide the density of your specific sample of CaCO3 to calculate its volume. If you have the density, please provide it, and I can help you calculate the volume.