Question

1)m(Na2O)=95 г W(O)=66% знайти W(O)-? m(O)-? 2)m(CuCi2)=150 г w(Cu)=78% знайти m(Ci)-? Допоможіть будь ласка:3

Answer 1

Ответ:

1)w(o)= 66% (?)

m(O)=62,5г

2)m(Cl)=117г

Объяснение:

W=mвва×100%/mсмеси, отсюда mвва= W×mсмесм/100%

пример: m(O)=66×95/100%=62,5г

для второго формула та же

т.к такого вещества как Ci я не знаю, я приму его за хлор(Cl).

Answer 2

Sure, I can help you with these problems. Let's take them one by one:

1. $m(Na_2O) = 95 \, \text{г}$, $W(O) = 66\%$

a) Find $W(O)$:

The molar mass of $Na_2O$ is the sum of the molar masses of sodium ($Na$) and oxygen ($O$).

• Molar mass of $Na_2O$ = $2 \times \text{Molar mass of Na} + \text{Molar mass of O}$

The molar masses are approximately 23 g/mol for Na and 16 g/mol for O.

$\text{Molar mass of } Na_2O = 2 \times 23 \, \text{g/mol} + 16 \, \text{g/mol} = 62 \, \text{g/mol}$

Now, you can find the moles of $Na_2O$ using the given mass:

$\text{Moles of } Na_2O = \frac{\text{Mass}}{\text{Molar mass}} = \frac{95 \, \text{g}}{62 \, \text{g/mol}}$

b) Find $W(O)$:

$W(O) = \frac{\text{Molar mass of O} \times \text{Moles of O}}{\text{Molar mass of } Na_2O}$

$W(O) = \frac{16 \, \text{g/mol} \times \text{Moles of O}}{62 \, \text{g/mol}}$

Given that $W(O) = 66\%$, you can set up the equation:

$66\% = \frac{16 \, \text{g/mol} \times \text{Moles of O}}{62 \, \text{g/mol}} \times 100$

Now, solve for $\text{Moles of O}$, then you can find $W(O)$.

2. $m(CuCl_2) = 150 \, \text{г}$, $w(Cu) = 78\%$

The molar mass of $CuCl_2$ is the sum of the molar masses of copper ($Cu$) and chlorine ($Cl$).

$\text{Molar mass of } CuCl_2 = \text{Molar mass of Cu} + 2 \times \text{Molar mass of Cl}$

Find the moles of $CuCl_2$ using the given mass:

$\text{Moles of } CuCl_2 = \frac{\text{Mass}}{\text{Molar mass}}$

Then, find the moles of $Cl$ using the stoichiometry of $CuCl_2$. The ratio of moles of $Cu$ to moles of $Cl$ is 1:2.

$\text{Moles of } Cl = 2 \times \text{Moles of } Cu$

Finally, find $m(Cl)$ using the moles of $Cl$ and the molar mass of $Cl$.

Feel free to use these guidelines to solve the problems, and let me know if you have any further questions or need additional clarification.