Question

A) Cu → CuO → CuSO4 → Cu(OH)2 → CuCl26) C → CO2 → BaCO3 + Ba(NO3)2 → BaSO4​

Answer 1

Ответ:

2Cu + O2 (изб.)→ 2CuO

CuO + H2SO4 → CuSO4 + H2O

CuSO4 + 2NaOH (разб.)→ Cu(OH)2 + Na2SO4

Cu(OH)2 + 2HCl (разб.)→ CuCl2 + 2H2O

C + O2 → CO2↑

BaO + CO2 → BaCO3

BaCO3 + 2HNO3 → Ba(NO3)2 + H2O + CO2↑

Ba(NO3)2 + H2SO4 (разб.)→ BaSO4 + 2HNO3

Объяснение:

Answer 2

It looks like you've provided two chemical reactions. I'll explain each of them:

1. The first reaction involves the conversion of copper (Cu) into several compounds:

   a) Cu → CuO: Copper (Cu) is oxidized to form copper(II) oxide (CuO). b) CuO → CuSO4: Copper(II) oxide reacts with sulfuric acid to produce copper(II) sulfate (CuSO4). c) CuSO4 → Cu(OH)2: Copper(II) sulfate reacts with a base to form copper(II) hydroxide (Cu(OH)2). d) Cu(OH)2 → CuCl2: Copper(II) hydroxide can react with hydrochloric acid (HCl) to produce copper(II) chloride (CuCl2).

2. The second reaction involves the conversion of carbon (C) into various compounds:

   a) C → CO2: Carbon (C) undergoes combustion to form carbon dioxide (CO2). b) CO2 → BaCO3 + Ba(NO3)2: Carbon dioxide (CO2) reacts with barium hydroxide (Ba(OH)2) to produce barium carbonate (BaCO3) and barium nitrate (Ba(NO3)2). c) BaCO3 → BaSO4: Barium carbonate (BaCO3) can react with sulfuric acid (H2SO4) to form barium sulfate (BaSO4).

These reactions represent a series of chemical transformations where one substance is converted into another through various chemical reactions. If you have any specific questions about these reactions or need more information, feel free to ask.