Question

Mr (Cu(NO3)3) Mr (Al2)SO4)3)Mr (Cl2O7) ​

Answer 1

Ответ:

1. 249.5607

2.Mr(Al2(SO4)3) =2*Ar(Al)+3*Ar(S)+12*Ar(O)=2*27+3*32+12*16=54+96+192=342

3. 182.9018

Объяснение:

Answer 2

Відповідь:

Mr (Cu(NO3)3)=64+14*3+16*3*3=250

Mr (Al2)SO4)3)=27*2+32*3+16*4*3=262

Mr (Cl2O7) ​=35,5*2+16*7=182

Пояснення:

Answer 3

It looks like you're providing chemical formulas and asking for the molar masses (Mr) of the compounds. Let's break it down:

1. Copper(III) nitrate, Cu(NO3)3:

   • Cu: Atomic mass = 63.55 g/mol
   • N: Atomic mass = 14.01 g/mol
   • O: Atomic mass = 16.00 g/mol (x3 for three oxygen atoms in the nitrate ion)

   Calculate: 63.55 + (14.01 + 3 * 16.00) * 3

2. Aluminum sulfate, Al2(SO4)3:

   • Al: Atomic mass = 26.98 g/mol (x2 for two aluminum atoms)
   • S: Atomic mass = 32.06 g/mol
   • O: Atomic mass = 16.00 g/mol (x4 for four oxygen atoms in the sulfate ion)

   Calculate: (2 * 26.98) + 32.06 + (16.00 * 4) * 3

3. Dichlorine heptoxide, Cl2O7:

   • Cl: Atomic mass = 35.45 g/mol (x2 for two chlorine atoms)
   • O: Atomic mass = 16.00 g/mol (x7 for seven oxygen atoms)

   Calculate: (35.45 * 2) + (16.00 * 7)

Feel free to plug in the numbers and do the math!