Question

1.     При взаимодействии нитрата меди с гидроксидом натрия образовалось 100г гидроксида меди. Рассчитайте массу гидроксида натрия, вступившего в реакцию.   Помогите похалуйста Дам 35 баллов с дано и решением))​

Answer 1

Ответ:

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Answer 2

To calculate the mass of sodium hydroxide that reacted with copper nitrate to form 100g of copper hydroxide, we need to use stoichiometry and the balanced chemical equation for the reaction.

The balanced chemical equation for the reaction between copper nitrate (Cu(NO3)2) and sodium hydroxide (NaOH) is:

Cu(NO3)2 + 2NaOH -> Cu(OH)2 + 2NaNO3

From the balanced equation, we can see that 1 mole of copper nitrate reacts with 2 moles of sodium hydroxide to produce 1 mole of copper hydroxide.

To calculate the mass of sodium hydroxide, we need to determine the number of moles of copper hydroxide formed. We can then use the mole ratio from the balanced equation to find the number of moles of sodium hydroxide.

Given that the mass of copper hydroxide formed is 100g, we can calculate the number of moles of copper hydroxide using its molar mass. The molar mass of copper hydroxide (Cu(OH)2) is:

(1 atom of copper x atomic mass of copper) + (2 atoms of oxygen x atomic mass of oxygen) + (2 atoms of hydrogen x atomic mass of hydrogen)

= (1 x 63.55 g/mol) + (2 x 16.00 g/mol) + (2 x 1.01 g/mol) = 63.55 g/mol + 32.00 g/mol + 2.02 g/mol = 97.57 g/mol

Now, we can calculate the number of moles of copper hydroxide:

moles of copper hydroxide = mass of copper hydroxide / molar mass of copper hydroxide moles of copper hydroxide = 100g / 97.57 g/mol moles of copper hydroxide ≈ 1.025 mol

Since the mole ratio between copper hydroxide and sodium hydroxide is 1:2, the number of moles of sodium hydroxide is twice the number of moles of copper hydroxide:

moles of sodium hydroxide = 2 x moles of copper hydroxide moles of sodium hydroxide ≈ 2.05 mol

Finally, we can calculate the mass of sodium hydroxide using its molar mass. The molar mass of sodium hydroxide (NaOH) is:

(1 atom of sodium x atomic mass of sodium) + (1 atom of oxygen x atomic mass of oxygen) + (1 atom of hydrogen x atomic mass of hydrogen)

= (1 x 22.99 g/mol) + (1 x 16.00 g/mol) + (1 x 1.01 g/mol) = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 40.00 g/mol

mass of sodium hydroxide = moles of sodium hydroxide x molar mass of sodium hydroxide mass of sodium hydroxide = 2.05 mol x 40.00 g/mol mass of sodium hydroxide ≈ 82 g

Therefore, the mass of sodium hydroxide that reacted with copper nitrate to form 100g of copper hydroxide is approximately 82 grams.

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