Question

Сделайте схему ковалентной химической связи PCl3. Пожалуйста!!!!! Срочно!!!!!! ​

Answer 1

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Answer 2

Covalent Bonding in PCl3

The molecule PCl3, also known as phosphorus trichloride, is formed through covalent bonding. Covalent bonding occurs when atoms share electrons to achieve a stable electron configuration. In the case of PCl3, phosphorus (P) and chlorine (Cl) atoms share electrons to form a stable molecule.

Phosphorus has an atomic number of 15, meaning it has 15 protons and 15 electrons. Chlorine has an atomic number of 17, with 17 protons and 17 electrons. To determine the number of valence electrons for each atom, we look at their position in the periodic table. Phosphorus is in Group 5A, so it has 5 valence electrons, while chlorine is in Group 7A, so it has 7 valence electrons.

To form a stable molecule, phosphorus needs to share three electrons, while each chlorine atom needs to share one electron. This results in three chlorine atoms bonding with one phosphorus atom, forming PCl3. The shared electrons create covalent bonds between the atoms.

Lewis Structure of PCl3

To represent the covalent bonds in PCl3, we can use a Lewis structure. In a Lewis structure, the valence electrons of each atom are represented as dots or lines. The dots represent the non-bonding electrons, while the lines represent the covalent bonds.

Here is the Lewis structure for PCl3:

   Cl
   |
   P
  / \
 Cl  Cl

In this structure, the phosphorus atom is in the center, surrounded by three chlorine atoms. Each chlorine atom shares one electron with the phosphorus atom, forming a single covalent bond. The remaining two valence electrons on each chlorine atom are represented as dots.

Conclusion

In summary, PCl3 is a molecule formed through covalent bonding. The phosphorus atom shares three electrons with three chlorine atoms, resulting in the formation of three covalent bonds. The Lewis structure of PCl3 shows the arrangement of atoms and the sharing of electrons in the molecule.

I hope this explanation helps! Let me know if you have any further questions.