Question

Обчислити відносну молекулярну масу складної речовини: а) що складається з 2 атомів Нітрогену і 5 атомів Оксигену; б) що складається з 3 атомів Калію, 1атому Фосфору і 4 атомів Оксигену; в) що має формулу Ca(OH)2; г) що має формулу Fe2(SO4)3.

Answer 1

Объяснение:

a)Mr(N2O5)=14*2+16*5=108gr/mol

b)Mr(K3PO4)=39*3+31+16*4=212gr/mol

c)Mr(Ca(OH)2)=40+17*2=74gr/mol

d)Mr(Fe(SO4)3=56+96+192=344gr/mol

Answer 2

Calculation of Relative Molecular Mass

To calculate the relative molecular mass (also known as the molar mass or molecular weight) of a compound, we need to determine the sum of the atomic masses of all the atoms in the compound.

a) For a compound composed of 2 nitrogen atoms (N) and 5 oxygen atoms (O), we can calculate the relative molecular mass as follows:

- Atomic mass of nitrogen (N) = 14.01 g/mol - Atomic mass of oxygen (O) = 16.00 g/mol

To calculate the relative molecular mass, we multiply the number of atoms by their respective atomic masses and sum them up:

Relative molecular mass = (2 * 14.01 g/mol) + (5 * 16.00 g/mol)

Relative molecular mass of the compound composed of 2 nitrogen atoms and 5 oxygen atoms = 2 * 14.01 g/mol + 5 * 16.00 g/mol = 108.07 g/mol [[1]].

b) For a compound composed of 3 potassium atoms (K), 1 phosphorus atom (P), and 4 oxygen atoms (O), we can calculate the relative molecular mass as follows:

- Atomic mass of potassium (K) = 39.10 g/mol - Atomic mass of phosphorus (P) = 30.97 g/mol - Atomic mass of oxygen (O) = 16.00 g/mol

Relative molecular mass = (3 * 39.10 g/mol) + (1 * 30.97 g/mol) + (4 * 16.00 g/mol)

Relative molecular mass of the compound composed of 3 potassium atoms, 1 phosphorus atom, and 4 oxygen atoms = 3 * 39.10 g/mol + 1 * 30.97 g/mol + 4 * 16.00 g/mol = 212.27 g/mol [[2]].

c) For a compound with the formula Ca(OH)2, we can calculate the relative molecular mass as follows:

- Atomic mass of calcium (Ca) = 40.08 g/mol - Atomic mass of oxygen (O) = 16.00 g/mol - Atomic mass of hydrogen (H) = 1.01 g/mol

Relative molecular mass = 40.08 g/mol + (2 * 1.01 g/mol) + (2 * 16.00 g/mol)

Relative molecular mass of the compound with the formula Ca(OH)2 = 40.08 g/mol + 2 * 1.01 g/mol + 2 * 16.00 g/mol = 74.09 g/mol [[3]].

d) For a compound with the formula Fe2(SO4)3, we can calculate the relative molecular mass as follows:

- Atomic mass of iron (Fe) = 55.85 g/mol - Atomic mass of sulfur (S) = 32.07 g/mol - Atomic mass of oxygen (O) = 16.00 g/mol

Relative molecular mass = (2 * 55.85 g/mol) + (3 * 32.07 g/mol) + (12 * 16.00 g/mol)

Relative molecular mass of the compound with the formula Fe2(SO4)3 = 2 * 55.85 g/mol + 3 * 32.07 g/mol + 12 * 16.00 g/mol = 399.88 g/mol [[4]].

In summary: a) The compound composed of 2 nitrogen atoms and 5 oxygen atoms has a relative molecular mass of 108.07 g/mol. b) The compound composed of 3 potassium atoms, 1 phosphorus atom, and 4 oxygen atoms has a relative molecular mass of 212.27 g/mol. c) The compound with the formula Ca(OH)2 has a relative molecular mass of 74.09 g/mol. d) The compound with the formula Fe2(SO4)3 has a relative molecular mass of 399.88 g/mol.