Question

If 20mL of 0.5N salt solution is diluted to 1L, What is the new concentration?

Answer 1

Ответ:

Here, Let M

1

(molarity H

2

SO

4

)=2M, V

1

(volume of H

2

SO

4

)=20ml=0.02L, V

2

(volume of solution)=1L and M

2

(molarity of resulting solution)=?

Therefore, M

1

×V

1

=M

2

×V

2

M

2

=0.04M

Normality=M

2

×n , here n is number of H

+

ions an acid can donate

Normality=0.04×2=0.08N

Answer 2

To calculate the new concentration of a solution after dilution, we can use the formula:

C1V1 = C2V2

Where: - C1 is the initial concentration of the solution - V1 is the initial volume of the solution - C2 is the final concentration of the solution - V2 is the final volume of the solution

In this case, we have an initial volume of 20 mL and an initial concentration of 0.5N. We want to dilute this solution to a final volume of 1L.

Let's substitute the values into the formula and solve for C2:

0.5N * 20 mL = C2 * 1000 mL

Simplifying the equation:

C2 = (0.5N * 20 mL) / 1000 mL

Calculating the value:

C2 = 10N / 1000

Therefore, the new concentration of the solution after dilution is 0.01N.

Please note that the above calculation assumes that the dilution is done by adding solvent (usually water) to the initial solution.