Question

Calculate the molar concentration( molarity) of 10% solution of H2so4 (density is 1.066 g/ml​

Answer 1

Ответ:

1,087 m/l

Объяснение:

Сm(H2SO4)=(1000*1.066*0.1)/98=1,087 m/l

Answer 2

To calculate the molar concentration (molarity) of a solution, we need to know the density of the solution and the percent concentration of the solute.

Given: Percent concentration of H2SO4 = 10% Density of the solution = 1.066 g/mL

To find the molarity, we need to convert the percent concentration to grams of solute per liter of solution and then calculate the number of moles of solute.

First, let's calculate the mass of H2SO4 in 1 mL of the solution: Mass of H2SO4 = (10/100) * 1 mL * 1.066 g/mL = 0.1066 g

Now, we need to convert the mass of H2SO4 to moles using the molar mass of H2SO4. The molar mass of H2SO4 is: H: 1.01 g/mol x 2 = 2.02 g/mol S: 32.07 g/mol O: 16.00 g/mol x 4 = 64.00 g/mol Total molar mass of H2SO4 = 98.09 g/mol

Number of moles of H2SO4 in 1 mL of the solution: Moles of H2SO4 = Mass of H2SO4 / Molar mass of H2SO4 = 0.1066 g / 98.09 g/mol ≈ 0.001086 mol

Since the density of the solution is given as 1.066 g/mL, it means that 1 mL of the solution has a mass of 1.066 g. Therefore, the volume of the solution containing 0.001086 mol of H2SO4 can be calculated as follows: Volume of the solution = Mass of the solution / Density of the solution = 1.066 g / 1.066 g/mL = 1 mL

Finally, to obtain the molarity, we divide the number of moles of H2SO4 by the volume of the solution in liters: Molarity (M) = Moles of H2SO4 / Volume of the solution in liters = 0.001086 mol / 0.001 L = 1.086 M

Therefore, the molar concentration (molarity) of the 10% H2SO4 solution is approximately 1.086 M.