Question

Какая масса раствора серной кислоты с массовой долей растворённого вещества 13 % необходима для полной нейтрализации раствора, содержащего 162 г гидроксида калия? Заполните таблицу. Проблема Что есть для решения Чего не хватает Решение

Answer 1

Ответ:

436,5г

на держи но конечно не кратко но правильно

Answer 2

Calculation of the Mass of Sulfuric Acid Solution Needed for Neutralization

To calculate the mass of sulfuric acid solution needed for the complete neutralization of a solution containing 162 g of potassium hydroxide (KOH), we can use the concept of stoichiometry. The balanced chemical equation for the neutralization reaction between sulfuric acid (H2SO4) and potassium hydroxide is as follows:

H2SO4 + 2KOH → K2SO4 + 2H2O

From the balanced equation, we can see that one mole of sulfuric acid reacts with two moles of potassium hydroxide. To determine the number of moles of potassium hydroxide in the given 162 g, we need to divide the mass by the molar mass of KOH.

The molar mass of KOH is calculated as follows: - The molar mass of potassium (K) is approximately 39.10 g/mol. - The molar mass of oxygen (O) is approximately 16.00 g/mol. - The molar mass of hydrogen (H) is approximately 1.01 g/mol.

Adding these values together, we find that the molar mass of KOH is approximately 56.11 g/mol.

Now, we can calculate the number of moles of KOH: Number of moles = Mass / Molar mass Number of moles = 162 g / 56.11 g/mol

Let's calculate the number of moles of KOH: Number of moles = 2.89 mol

Since the stoichiometric ratio between sulfuric acid and potassium hydroxide is 1:2, we need twice the number of moles of sulfuric acid to neutralize the given amount of potassium hydroxide.

Therefore, the number of moles of sulfuric acid needed is: Number of moles of H2SO4 = 2 * Number of moles of KOH Number of moles of H2SO4 = 2 * 2.89 mol

Now, we can calculate the mass of sulfuric acid needed using the number of moles and the molar mass of H2SO4.

The molar mass of H2SO4 is calculated as follows: - The molar mass of sulfur (S) is approximately 32.07 g/mol. - The molar mass of oxygen (O) is approximately 16.00 g/mol. - The molar mass of hydrogen (H) is approximately 1.01 g/mol.

Adding these values together, we find that the molar mass of H2SO4 is approximately 98.09 g/mol.

Now, let's calculate the mass of sulfuric acid needed: Mass of H2SO4 = Number of moles of H2SO4 * Molar mass of H2SO4 Mass of H2SO4 = 2 * 2.89 mol * 98.09 g/mol

Using the above calculation, we find that the mass of sulfuric acid needed for the complete neutralization of the given solution is approximately 566.57 g.

Table:

| Substance | Mass (g) | |---------------------|----------| | Potassium Hydroxide | 162 | | Sulfuric Acid | 566.57 |

Note: The above calculations assume that the reaction goes to completion and that there are no other reactions or side reactions taking place.