Question

смесь циклобутана и циклопентана массой 38 г воздействовали достаточным количеством хлора в результате выделилось 4,48 л нормальные условия газа. определить объемную долю% циклопентана начальной смеси.​

Answer 1

Ответ:

545

Объяснение:

Answer 2

To determine the volumetric percentage of cyclopentane in the initial mixture, we can use the ideal gas law and the concept of partial pressures. The ideal gas law states that the pressure, volume, and temperature of a gas are related by the equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

In this case, we are given the volume of gas produced (4.48 L) and the mass of the initial mixture (38 g). To find the number of moles of gas produced, we need to convert the mass of the initial mixture to moles. We can do this by dividing the mass by the molar mass of the mixture.

To find the molar mass of the mixture, we need to know the molar masses of cyclobutane and cyclopentane. According to the periodic table, the molar masses of carbon (C) and hydrogen (H) are approximately 12.01 g/mol and 1.01 g/mol, respectively.

The molar mass of cyclobutane (C4H8) can be calculated as follows: (4 * molar mass of carbon) + (8 * molar mass of hydrogen) = (4 * 12.01 g/mol) + (8 * 1.01 g/mol) = 56.08 g/mol.

Similarly, the molar mass of cyclopentane (C5H10) can be calculated as follows: (5 * molar mass of carbon) + (10 * molar mass of hydrogen) = (5 * 12.01 g/mol) + (10 * 1.01 g/mol) = 70.14 g/mol.

Now we can calculate the number of moles of gas produced: moles of gas = mass of gas / molar mass of gas moles of gas = 38 g / (56.08 g/mol + 70.14 g/mol) = 0.303 mol.

Since the reaction is assumed to be complete, the number of moles of gas produced is equal to the number of moles of cyclopentane in the initial mixture. Therefore, the volumetric percentage of cyclopentane can be calculated as follows: volumetric percentage of cyclopentane = (moles of cyclopentane / total moles of gas) * 100 volumetric percentage of cyclopentane = (0.303 mol / 0.303 mol) * 100 = 100%.

Therefore, the initial mixture is 100% cyclopentane.

Please note that the calculations above assume ideal gas behavior and complete reaction.