Question

10.Сколько воды образуется, если при сгорании водорода участвовало 100л кислорода?​

Answer 1

Объяснение:

2h2+o2=2h2o

100-----x

22.4--(18гр×2)=36

100×36/22.4~~161 гр воды

Answer 2

Ответ:

Ответ: 81 грамм........

Answer 3

Calculating the Amount of Water Produced from the Combustion of Hydrogen and Oxygen

To calculate the amount of water produced when 100 liters of oxygen is involved in the combustion of hydrogen, we can use the balanced chemical equation for the reaction between hydrogen and oxygen to form water.

The balanced chemical equation for the reaction is: 2H2 + O2 → 2H2O

From the balanced equation, we can see that 2 moles of hydrogen react with 1 mole of oxygen to produce 2 moles of water.

Given that 100 liters of oxygen is involved, we need to calculate the corresponding amount of hydrogen and the resulting water produced.

Calculation:

1. Convert 100 liters of oxygen to moles: - Using the ideal gas law, 1 mole of any gas occupies 22.4 liters at standard temperature and pressure (STP). - Therefore, 100 liters of oxygen is equal to 100/22.4 = 4.46 moles of oxygen.

2. Determine the amount of hydrogen required: - According to the balanced chemical equation, the molar ratio of hydrogen to oxygen is 2:1. - So, the amount of hydrogen required is 2 * 4.46 = 8.92 moles.

3. Calculate the amount of water produced: - Since 2 moles of water are produced for every 2 moles of hydrogen, the amount of water produced is also 8.92 moles.

Answer:

The amount of water produced when 100 liters of oxygen is involved in the combustion of hydrogen is 8.92 moles.