Question

СРОЧНО, ДАМ 50 БАЛЛОВ сколько г щелочи нужно добавить к 2 л 0,5 м раствора гидроксида натрия(плотность 1,1г/мл) чтобы сделать его массовую долю 20%?округлять ответ до целых чиселс решением, пожалуйста​

Answer 1

Тут очень сложно,надо немного порешать думаю через минут 5-10 решу и дам ответ

Answer 2

Calculating the Amount of Sodium Hydroxide Needed

To calculate the amount of sodium hydroxide needed to make a 20% mass fraction solution, we can use the following steps:

1. Determine the Mass of the Solution: - The mass of the solution can be calculated using the density and volume of the solution. - Given: - Volume of the solution (V) = 2 L - Density of sodium hydroxide solution (ρ) = 1.1 g/mL - Mass of the solution (m_solution) = Volume × Density - m_solution = V × ρ - m_solution = 2 L × 1.1 g/mL - m_solution = 2.2 kg

2. Calculate the Mass of Sodium Hydroxide Needed: - We can use the mass fraction formula to find the mass of sodium hydroxide required. - Given: - Mass fraction of sodium hydroxide (w) = 20% - Mass of sodium hydroxide (m_NaOH) = Mass of solution × Mass fraction - m_NaOH = m_solution × w - m_NaOH = 2.2 kg × 20% - m_NaOH = 0.44 kg

3. Convert Mass to Grams: - To convert the mass to grams, we can use the fact that 1 kg = 1000 g. - m_NaOH_grams = m_NaOH × 1000 - m_NaOH_grams = 0.44 kg × 1000 - m_NaOH_grams = 440 g

Therefore, 440 grams of sodium hydroxide need to be added to 2 liters of a 0.5 M sodium hydroxide solution to make it a 20% mass fraction solution.

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