Question

Скільки атомів міститься у воді масою 1,8 грам?​

Answer 1

Ответ:

n(H2O)=m(H2O):M(H2O)=1,8:18=0,1

N(H2O)=n×Na=0,1×6×10²³=0,6×10²³

Ответ:0,6×10²³

Answer 2

Calculating the Number of Atoms in 1.8 Grams of Water

To calculate the number of atoms in 1.8 grams of water, we can use the following steps:

1. Determine the Molar Mass of Water: - The molar mass of water (H2O) is approximately 18.01528 grams per mole.

2. Calculate the Number of Moles: - We can use the formula: \[ \text{Number of moles} = \frac{\text{Mass (in grams)}}{\text{Molar mass}} \] - Substituting the given mass of 1.8 grams and the molar mass of water, we get: \[ \text{Number of moles} = \frac{1.8 \, \text{g}}{18.01528 \, \text{g/mol}} \approx 0.09998 \, \text{moles} \]

3. Calculate the Number of Atoms: - Since 1 mole of a substance contains Avogadro's number of entities (atoms, molecules, ions, etc.), which is approximately \(6.022 \times 10^{23}\) entities per mole, we can calculate the number of atoms in 1.8 grams of water: \[ \text{Number of atoms} = \text{Number of moles} \times 6.022 \times 10^{23} \] - Substituting the number of moles, we get: \[ \text{Number of atoms} \approx 0.09998 \, \text{moles} \times 6.022 \times 10^{23} \approx 6.02 \times 10^{22} \, \text{atoms} \]

Therefore, there are approximately 6.02 x 10^22 atoms in 1.8 grams of water.