Question

ОЧЕНЬ СРОЧНО!!!!! Определите объём (н.у., л) аммиака,который получится при действии избытка раствора гидроксида натрия на 48 г карбоната аммония,если выход в реакции составляет 70% ?

Answer 1

Ответ:

15.68л

Объяснение:

Дано                                             Решение

m ((NH4)2CO3) = 48г                      (NH4)2CO3 + 2NaOH = Na2CO3 + 2NH3 + H2O

n = 70% = 0,7                                 v ((NH4)2CO3) = m((NH4)2CO3) / M((NH4)2CO3) = 48 / 96 =

Найти:                                            = 0,5 моль

V (NH3) - ?                                     v (NH3) = v((NH4)2CO3) ⋅ 2 = 1 моль

                                                    Vтеор (NH3) = 1 ⋅ 22,4 = 22,4 л

                                                    Vпрак (NH3) = 22,4 ⋅ 0,7 = 15,68 л (выводится из формулы                                                       выхода реакции n = Vпрак / Vтеор)

                                                    Ответ: 15,68 л

Answer 2

Calculation of Ammonia Volume

To calculate the volume of ammonia produced when excess sodium hydroxide solution reacts with 48 g of ammonium carbonate, we need to consider the balanced chemical equation for the reaction and the given yield.

The balanced chemical equation for the reaction is:

NH4CO3 + 2NaOH → Na2CO3 + 2H2O + 2NH3

According to the equation, 1 mole of ammonium carbonate (NH4CO3) reacts with 2 moles of sodium hydroxide (NaOH) to produce 2 moles of ammonia (NH3).

To find the number of moles of ammonium carbonate, we can use its molar mass. The molar mass of ammonium carbonate (NH4CO3) is calculated as follows:

NH4CO3: (1 * 14.01 g/mol) + (4 * 1.01 g/mol) + (1 * 12.01 g/mol) + (3 * 16.00 g/mol) = 96.09 g/mol

Therefore, the number of moles of ammonium carbonate is:

48 g / 96.09 g/mol = 0.4997 mol

Since the reaction has a yield of 70%, we can calculate the number of moles of ammonia produced:

0.4997 mol * 70% = 0.3498 mol

Finally, to find the volume of ammonia, we need to convert moles to volume using the ideal gas law. The molar volume of an ideal gas at standard temperature and pressure (STP) is 22.4 L/mol.

Volume of ammonia = 0.3498 mol * 22.4 L/mol = 7.82 L

Therefore, the volume of ammonia produced when excess sodium hydroxide solution reacts with 48 g of ammonium carbonate, with a yield of 70%, is approximately 7.82 liters.

Please note that this calculation assumes ideal conditions and may not account for any deviations from the ideal gas law or other factors that may affect the reaction.