Question

Определите объём (н.у., л) аммиака,который получится при действии избытка раствора гидроксида натрия на 48 г карбоната аммония,если выход в реакции составляет 70% ?

Answer 1

Ответ: лови, неизвестный ученик 9А, 30-ой школы))

Объяснение:

Не знала, что у меня в нашем классе есть тезка))

Answer 2

Calculation of Ammonia Volume

To determine the volume of ammonia produced when excess sodium hydroxide solution reacts with 48 g of ammonium carbonate, we need to consider the reaction equation and the given information.

The balanced chemical equation for the reaction between ammonium carbonate and sodium hydroxide is:

(NH4)2CO3 + 2NaOH → 2NH3 + H2O + Na2CO3

From the equation, we can see that 1 mole of ammonium carbonate reacts to produce 2 moles of ammonia. To calculate the moles of ammonium carbonate, we need to divide the given mass by the molar mass of ammonium carbonate.

The molar mass of ammonium carbonate (NH4)2CO3 can be calculated as follows:

Molar mass of (NH4)2CO3 = (2 * molar mass of NH4) + molar mass of CO3

The molar mass of NH4 is 14.01 g/mol, and the molar mass of CO3 is 60.01 g/mol.

Molar mass of (NH4)2CO3 = (2 * 14.01) + 60.01 = 96.03 g/mol

Now, we can calculate the moles of ammonium carbonate:

Moles of (NH4)2CO3 = Mass of (NH4)2CO3 / Molar mass of (NH4)2CO3

Moles of (NH4)2CO3 = 48 g / 96.03 g/mol = 0.4997 mol

Since the reaction has a 2:2 mole ratio between ammonium carbonate and ammonia, the moles of ammonia produced will be the same as the moles of ammonium carbonate.

Moles of NH3 = 0.4997 mol

However, the given information states that the reaction has