Question

А. Аl + НCl = АlCl3 + …. б. …+ О2 = МgО в. Н2О + …. = H2SO4 г. Сu(ОН)2 +…. = СuCl2 + Н2О д. СаСО3 = …. + СО2 е. СuО + ….. = Сu SO4 + Н2О ж. Аl2(SO4)3 + ВаCl2 = ……+ АlCl3 з. К2О + … = КОН и. Na + Cl2 = …. к. Fе2(SO4)3 + …. = Fе(ОН)3 + Na2SO4 л. KOH + …= КCl + H2O

Answer 1

Ответ:

А) 2Аl + 6НCl = 2АlCl3 + 3Н2

Б) 2Мg+ О2 = 2МgО

В)2Н2О + H2SO4 =  2H3O + SO4

г. Сu(ОН)2 +2HCl = СuCl2 + 2Н2О

д. СаСО3 =CaO+ СО2

е. СuО +H2SO4  = СuSO4 + Н2О

ж. Аl2(SO4)3 + 3ВаCl2 = 3BaSO4+ 2АlCl3

з. К2О +H2O   = 2КОН

и. 2Na + Cl2 = 2NaCl

к. Fе2(SO4)3 + 6 NaOH= 2Fе(ОН)3 + 3Na2SO4

л. KOH +HCl = КCl + H2O

Объяснение:

Answer 2

Chemical Equations

a. The reaction of aluminum with hydrochloric acid produces aluminum chloride and hydrogen gas: - Al + HCl = AlCl3 + H2

b. The reaction of oxygen with magnesium produces magnesium oxide: - 2 Mg + O2 = 2 MgO

c. When water is added to sulfuric acid, it forms sulfuric acid solution: - H2O + H2SO4 = H2SO4

d. Copper(II) hydroxide reacts with hydrochloric acid to produce copper(II) chloride and water: - Cu(OH)2 + 2 HCl = CuCl2 + 2 H2O

e. Copper(II) oxide reacts with sulfuric acid to produce copper(II) sulfate and water: - CuO + H2SO4 = CuSO4 + H2O

f. The reaction between aluminum sulfate and barium chloride produces aluminum chloride and barium sulfate: - Al2(SO4)3 + 3 BaCl2 = 2 AlCl3 + 3 BaSO4

g. Potassium oxide reacts with water to form potassium hydroxide: - K2O + H2O = 2 KOH

h. Sodium reacts with chlorine gas to produce sodium chloride: - 2 Na + Cl2 = 2 NaCl

i. Iron(III) sulfate reacts with sodium hydroxide to produce iron(III) hydroxide, sodium sulfate, and water: - Fe2(SO4)3 + 6 NaOH = 2 Fe(OH)3 + 3 Na2SO4

j. Potassium hydroxide reacts with hydrochloric acid to produce potassium chloride and water: - KOH + HCl = KCl + H2O

These chemical equations illustrate various reactions involving different substances. If you have any specific questions about these reactions or chemistry in general, feel free to ask!