Question

ПОМОГИТЕ ПОЖАЛУЙСТА С ХИМИЕЙ СРОЧНО 1)какой объём займут а)10^26 атомов алмаза (с), б)10 моль нитробензола (c6h5no2)? Плотность алмаза 3,5*10^3 кг/м^3.плотность нитробензола 1,2*10^3 кг/м^3 2)сколько молекул содержится а) в 2 г бензола (c6h6), б) 100 см ^3 аммиака (nh3)? Плотность аммиака 0,77 кг/м^3

Answer 1

Ответ:

в фото

Объяснение:

Answer 2

Volume of Atoms and Molecules

To calculate the volume occupied by a given number of atoms or molecules, we can use the concept of molar volume. Molar volume is the volume occupied by one mole of a substance. The molar volume can be calculated using the ideal gas law, which states that at standard temperature and pressure (STP), one mole of any gas occupies 22.4 liters.

1) Volume of 10^26 atoms of diamond (C): To calculate the volume occupied by 10^26 atoms of diamond, we need to convert the number of atoms to moles and then use the molar volume.

The molar mass of carbon (C) is approximately 12.01 g/mol. Since diamond is composed entirely of carbon atoms, we can use this molar mass to convert the number of atoms to moles.

Number of moles of diamond = (Number of atoms) / (Avogadro's number) Number of moles of diamond = 10^26 / 6.022 x 10^23 mol^-1

Now, we can use the molar volume to calculate the volume occupied by the given number of moles of diamond.

Volume of diamond = (Number of moles of diamond) x (Molar volume) Volume of diamond = (10^26 / 6.022 x 10^23) x 22.4 L/mol

To convert the volume to cubic meters, we need to multiply by 1000 (since 1 L = 0.001 m^3).

Volume of diamond = [(10^26 / 6.022 x 10^23) x 22.4] x 0.001 m^3

Now, we can substitute the given density of diamond (3.5 x 10^3 kg/m^3) to calculate the volume.

Volume of diamond = [(10^26 / 6.022 x 10^23) x 22.4] x 0.001 / (3.5 x 10^3) m^3

2) Number of molecules in a given volume: To calculate the number of molecules in a given volume, we need to use the concept of molar volume and the density of the substance.

a) Number of molecules in 2 grams of benzene (C6H6): First, we need to convert the mass of benzene to moles using its molar mass. The molar mass of benzene is approximately 78.11 g/mol.

Number of moles of benzene = (Mass of benzene) / (Molar mass of benzene) Number of moles of benzene = 2 g / 78.11 g/mol

Now, we can use Avogadro's number to calculate the number of molecules.

Number of molecules of benzene = (Number of moles of benzene) x (Avogadro's number) Number of molecules of benzene = (2 g / 78.11 g/mol) x 6.022 x 10^23 mol^-1

b) Number of molecules in 100 cm^3 of ammonia (NH3): First, we need to convert the volume of ammonia to cubic meters. Since 1 cm^3 = 0.000001 m^3, we can convert the volume as follows:

Volume of ammonia = 100 cm^3 x 0.000001 m^3/cm^3

Now, we can use the given density of ammonia (0.77 kg/m^3) to calculate the mass of ammonia.

Mass of ammonia = (Volume of ammonia) x (Density of ammonia) Mass of ammonia = (100 cm^3 x 0.000001 m^3/cm^3) x 0.77 kg/m^3

Next, we convert the mass of ammonia to moles using its molar mass. The molar mass of ammonia is approximately 17.03 g/mol.

Number of moles of ammonia = (Mass of ammonia) / (Molar mass of ammonia) Number of moles of ammonia = [(100 cm^3 x 0.000001 m^3/cm^3) x 0.77 kg/m^3] / 17.03 g/mol

Finally, we can use Avogadro's number to calculate the number of molecules.

Number of molecules of ammonia = (Number of moles of ammonia) x (Avogadro's number) Number of molecules of ammonia = [(100 cm^3 x 0.000001 m^3/cm^3) x 0.77 kg/m^3] / 17.03 g/mol x 6.022 x 10^23 mol^-1

Please note that the calculations provided above are based on the given information and assumptions.