Question

ДАЮ 100 БАЛІВ СРОЧНО Обчисліть молярну масу газу, якщо його густина (н. у.) 1,34 г/л. Розв'язок надрукуйте тут.​

Answer 1

Ответ:

30г моль

Объяснение:

Використовую формулу m / M = V / Vm і велечину газу = m/V = 1,34 г/л маємо: 22,4 л/моль множимо на 1,34 г/л отримуємо 30г / моль

Answer 2

I can help you with your homework, but I cannot do it for you. Here is a hint on how to solve this problem:

The molar mass of a gas can be calculated from its density and the ideal gas law: $$PV = nRT$$ where P is the pressure, V is the volume, n is the number of moles, R is the universal gas constant, and T is the temperature.

If you rearrange this equation, you get: $$\frac{n}{V} = \frac{P}{RT}$$ The ratio of n to V is the same as the molar concentration of the gas, which is measured in moles per liter. The density of the gas is the mass per unit volume, which is measured in grams per liter. Therefore, the molar mass of the gas is the ratio of the density to the molar concentration: $$M = \frac{\rho}{\frac{n}{V}} = \frac{\rho}{\frac{P}{RT}}$$ where M is the molar mass and $\rho$ is the density.

To find the molar mass of the gas, you need to know its density, the pressure, the temperature, and the value of R. The density is given in the problem as 1.34 g/L. The pressure and the temperature are the standard conditions, which are 1 atm and 273.15 K. The value of R is 0.08206 L atm / K mol.

Plug these values into the formula and you get: $$M = \frac{1.34}{\frac{1}{0.08206 \times 273.15}} = 29.88$$ The molar mass of the gas is 29.88 g/mol.

I hope this helps you understand how to solve this problem. Good luck with your homework!Ответь+подробно.++ДАЮ+100+БАЛІВ+СРОЧНО+Обчисліть+молярну+масу+газу,+якщо+його+густина+(н.+у.)+1,34+г/л.+Розв\'язок+надрукуйте+тут.​+