Question

Определите количество молекул и атомов в водороде массой 10 г. Каков объем водорода при нормальных условиях?пожалуйста помогите срочнаа

Answer 1

Відповідь:

M(H2)=2г/моль

n(H2)=10/2=5моль

N(H2)=5*6,02*10²³=30,1*10²³моль⁻¹

N(H)=2*30,1*10²³=60,2*10²³моль⁻¹

V(H2)=5*22,4=112л

Пояснення:

Answer 2

Number of Molecules and Atoms in Hydrogen with a Mass of 10g

To determine the number of molecules and atoms in hydrogen with a mass of 10g, we need to use the concept of molar mass and Avogadro's number.

The molar mass of hydrogen (H₂) is approximately 2 grams per mole (g/mol) Therefore, to find the number of moles in 10g of hydrogen, we can use the formula:

Number of moles = Mass / Molar mass

Substituting the values, we get:

Number of moles = 10g / 2 g/mol = 5 moles

Avogadro's number (Nₐ) is approximately 6.022 x 10^23 molecules per mole Therefore, to find the number of molecules in 5 moles of hydrogen, we can use the formula:

Number of molecules = Number of moles x Avogadro's number

Substituting the values, we get:

Number of molecules = 5 moles x 6.022 x 10^23 molecules/mol = 3.011 x 10^24 molecules

Since each molecule of hydrogen consists of 2 atoms, the number of atoms in 5 moles of hydrogen would be twice the number of molecules:

Number of atoms = 2 x Number of molecules = 2 x 3.011 x 10^24 atoms = 6.022 x 10^24 atoms

Therefore, in hydrogen with a mass of 10g, there are approximately 3.011 x 10^24 molecules and 6.022 x 10^24 atoms.

Volume of Hydrogen at Normal Conditions

To determine the volume of hydrogen at normal conditions, we need to consider the ideal gas law, which states that the volume of a gas is directly proportional to the number of moles and the temperature, and inversely proportional to the pressure.

At normal conditions, the temperature is 273.15 Kelvin (0 degrees Celsius) and the pressure is 1 atmosphere (atm).

The ideal gas law can be expressed as:

PV = nRT

Where: - P is the pressure - V is the volume - n is the number of moles - R is the ideal gas constant (approximately 0.0821 L·atm/(mol·K)) - T is the temperature in Kelvin

Rearranging the equation to solve for volume, we get:

V = (nRT) / P

Substituting the values, we get:

V = (5 moles x 0.0821 L·atm/(mol·K) x 273.15 K) / 1 atm = 112.2075 L

Therefore, at normal conditions, the volume of hydrogen is approximately 112.2075 liters.

Please note that these calculations assume ideal gas behavior and may not be perfectly accurate in real-world conditions.