
Помогите пожалуйста! Очень надо, как модно подробнее Воздух какого объёма необходим для полного
сгорания водорода и массой 1 кг?Объемная доля кислорода в воздухе равна 21%.

Ответы на вопрос

Ответ:
1 кг V м3 2H2+O2=2H2O 2*2 кг 22.4 м3 1/4=v/22.4 v=5.6 м3 O2 V воздуха=5.6*100/21=26.7 м3.



Calculating the Volume of Air Needed for Complete Combustion of 1 kg of Hydrogen
To calculate the volume of air needed for the complete combustion of 1 kg of hydrogen, we can use the stoichiometric ratio of hydrogen to oxygen in the combustion reaction. The balanced chemical equation for the combustion of hydrogen is:
2H2 + O2 → 2H2O
This equation shows that 2 moles of hydrogen react with 1 mole of oxygen to produce 2 moles of water. From this equation, we can determine the stoichiometric ratio of hydrogen to oxygen, which is 2:1.
Given that the volumetric fraction of oxygen in air is 21%, we can use this information to calculate the volume of air needed for the complete combustion of 1 kg of hydrogen.
Calculation
1. Molar Mass of Hydrogen (H2): - The molar mass of hydrogen is approximately 2 g/mol.
2. Molar Mass of Oxygen (O2): - The molar mass of oxygen is approximately 32 g/mol.
3. Moles of Hydrogen (H2) in 1 kg: - Moles of hydrogen = Mass of hydrogen / Molar mass of hydrogen - Moles of hydrogen = 1000 g / 2 g/mol - Moles of hydrogen ≈ 500 moles
4. Moles of Oxygen (O2) Needed: - From the stoichiometric ratio, moles of oxygen needed = 0.5 * 2 = 1 mole
5. Volume of Air Needed: - Since the volumetric fraction of oxygen in air is 21%, the volumetric fraction of nitrogen is 79%. - The volume of air needed = Volume of oxygen / 0.21 - The volume of air needed = Volume of oxygen / 0.21 ≈ Volume of oxygen / (1/0.21) ≈ Volume of oxygen * 4.76
6. Conclusion: - The volume of air needed for the complete combustion of 1 kg of hydrogen can be calculated based on the above steps.
Conclusion
The volume of air needed for the complete combustion of 1 kg of hydrogen can be calculated using the stoichiometric ratio of hydrogen to oxygen and the volumetric fraction of oxygen in air. Based on the calculations, the volume of air needed is approximately 4.76 times the volume of oxygen required for the combustion of 1 kg of hydrogen.(#)
Let me know if you need further assistance with this!


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