Question

В реакцию с водой вступило 14 кг оксида кальция. Какая масса гидроксида кальция образовалась? При проведении расчетов массу оксида кальция перевести в граммы!!!

Answer 1

Ответ:

18.5г

Объяснение:

CaO+H2O=Ca(OH)2

M(CaO)=40+16=56г/моль

m(CaO)=14г

N(CaO)=14:56=0.25моль

M(Ca(OH)2)=40+2*(16+1)=74г/моль

N(CaO)=N(Ca(OH)2)=0.25моль

m(Ca(OH)2)=74*0.25=18.5г

Answer 2

Calculating the Mass of Calcium Hydroxide Formed

To calculate the mass of calcium hydroxide formed when 14 kg of calcium oxide reacts with water, we can use the following chemical equation for the reaction:

CaO + H2O → Ca(OH)2

First, we need to convert the mass of calcium oxide from kilograms to grams. Then, we can use stoichiometry to determine the mass of calcium hydroxide formed.

Conversion of Mass from Kilograms to Grams

The given mass of calcium oxide is 14 kg. To convert this to grams, we use the conversion factor: 1 kg = 1000 grams

So, 14 kg = 14 * 1000 = 14000 grams.

Using Stoichiometry to Calculate the Mass of Calcium Hydroxide

The molar mass of calcium oxide (CaO) is approximately 56.08 g/mol, and the molar mass of calcium hydroxide (Ca(OH)2) is approximately 74.09 g/mol.

From the balanced chemical equation: 1 mole of CaO reacts to form 1 mole of Ca(OH)2.

Now, we can calculate the number of moles of CaO using its molar mass and then use the mole ratio to find the moles of Ca(OH)2 formed. Finally, we can convert the moles of Ca(OH)2 to grams.

Let's perform the calculation:

Molar mass of CaO = 56.08 g/mol Molar mass of Ca(OH)2 = 74.09 g/mol

Given mass of CaO = 14000 grams

Using the molar mass of CaO: Number of moles of CaO = Given mass / Molar mass = 14000 g / 56.08 g/mol = 249.822 moles

Since the mole ratio is 1:1, the number of moles of Ca(OH)2 formed is also 249.822 moles.

Finally, the mass of Ca(OH)2 formed: Mass = Number of moles * Molar mass = 249.822 moles * 74.09 g/mol = 18515.45 grams

The mass of calcium hydroxide formed is approximately 18515.45 grams when 14 kg of calcium oxide reacts with water.