Question

Mr: C6H5OH, Na2SO4, CU(OH)2​

Answer 1

Ответ:

Mr(C6H5OH)=Ar(C)*6+Ar(H)*5+Ar(O)+Ar(H)=12*6+1*5+16+1=382
Mr(Na2SO4)=Ar(Na)*2=Ar(S)+Ar(O)*4=23*2+32+16*4=376
Mr=64+(16+1)*2=64+34=98 г/моль

Объяснение:Вот как-то так

 

Answer 2

Hello! It seems you have provided chemical formulas for three compounds: C6H5OH, Na2SO4, and Cu(OH)2.

1. C6H5OH: This formula represents a common organic compound known as phenol or hydroxybenzene. It consists of a benzene ring (C6H6) with a hydroxyl group (OH) attached to it. Phenol is used in various industrial processes, including the production of plastics, pharmaceuticals, and disinfectants.

2. Na2SO4: This formula represents sodium sulfate. It is an inorganic compound composed of sodium ions (Na+) and sulfate ions (SO4^2-). Sodium sulfate is commonly used in detergents, textile dyeing, and as a laboratory reagent. It also occurs naturally as a mineral called thenardite.

3. Cu(OH)2: This formula represents copper(II) hydroxide. It is an inorganic compound consisting of copper ions (Cu2+) and hydroxide ions (OH-). Copper(II) hydroxide is a blue solid and is often used as a fungicide and an ingredient in certain paints and pigments.

If you have any specific questions or need further information about these compounds, feel free to ask!