Question

Дописати рівняння реакцій, розставити коефіцієнти: 1) CuS + O2 →2) ZnS + O2 →3) C3H8 + O2 →4) PH3 + O2 →5) CS + O2 →6) CH3OH + O2 →Если сможете, сделайте быстро...Заранее спасибо)

Answer 1

Ответ:

Объяснение:

1) 2 CuS + 3 O2 → 2 CuO + 2 SO2

2) 2 ZnS + 3 O2 → 2 ZnO + 2 SO2

3) C3H8 +5 O2 =3 CO2 + 4 H2O

4) 2 PH3 + 4 O2 → P2O5 + 3 H2O

5) 2 Cs + O2 → Cs2O2

6) 2CH3OH + 3O2 → 2CO2 + 4H2O

Answer 2

1) CuS + O2 → 2 ZnS + O2 2) ZnS + O2 → 3 C3H8 + O2 3) C3H8 + O2 → 4 PH3 + O2 4) PH3 + O2 → 5 CS + O2 5) CS + O2 → 6 CH3OH + O2

To balance these chemical equations, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's go through each equation and balance them one by one:

1) CuS + O2 → 2 ZnS + O2 To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides. In this case, we have: - Cu: 1 on the left, 0 on the right - S: 1 on the left, 2 on the right - O: 2 on the left, 2 on the right

To balance the equation, we can add a coefficient of 2 in front of CuS on the left side: 2 CuS + O2 → 2 ZnS + O2

2) ZnS + O2 → 3 C3H8 + O2 In this equation, we have: - Zn: 1 on the left, 0 on the right - S: 1 on the left, 0 on the right - O: 2 on the left, 2 on the right - C: 0 on the left, 3 on the right - H: 0 on the left, 8 on the right

To balance the equation, we can add coefficients of 3 in front of ZnS and 4 in front of O2 on the right side: ZnS + 3 O2 → 3 C3H8 + 4 O2

3) C3H8 + O2 → 4 PH3 + O2 In this equation, we have: - C: 3 on the left, 0 on the right - H: 8 on the left, 0 on the right - O: 2 on the left, 2 on the right - P: 0 on the left, 4 on the right

To balance the equation, we can add coefficients of 4 in front of PH3 on the right side: C3H8 + O2 → 4 PH3 + O2

4) PH3 + O2 → 5 CS + O2 In this equation, we have: - P: 1 on the left, 0 on the right - H: 3 on the left, 0 on the right - O: 2 on the left, 2 on the right - C: 0 on the left, 5 on the right - S: 0 on the left, 0 on the right

To balance the equation, we can add coefficients of 5 in front of CS on the right side: PH3 + O2 → 5 CS + O2

5) CS + O2 → 6 CH3OH + O2 In this equation, we have: - C: 1 on the left, 1 on the right - S: 1 on the left, 0 on the right - O: 2 on the left, 2 on the right - H: 0 on the left, 6 on the right

To balance the equation, we can add coefficients of 6 in front of CH3OH on the right side: CS + O2 → 6 CH3OH + O2

So, the balanced equations are: 1) 2 CuS + O2 → 2 ZnS + O2 2) ZnS + 3 O2 → 3 C3H8 + 4 O2 3) C3H8 + O2 → 4 PH3 + O2 4) PH3 + O2 → 5 CS + O2 5) CS + O2 → 6 CH3OH + O2

I hope this helps! Let me know if you have any further questions.