Question

Помогите с химией пожалуйста Рассчитайте массу 40 % раствора серной кислоты необходимой для нейтрализации 80 г гидроксида натрия.​

Answer 1

Уравнение реакции

H2SO4 + 2NaOH = Na2SO4 + 2H2O

n(NaOH) = 80/40 = 2 моль

n(H2SO4) = 4 моль ( по уравнению )

m(H2SO4) = 4 × 98 = 392 грамм

m(р-ра H2SO4) = 392 - 40%

x - 100%

х = 392 × 100/40 = 980 грамм

Ответ: 980 грамм

Answer 2

Calculating the Mass of 40% Sulfuric Acid Solution Needed to Neutralize 80g of Sodium Hydroxide

To calculate the mass of a 40% sulfuric acid solution needed to neutralize 80g of sodium hydroxide, we can use the concept of stoichiometry and the balanced chemical equation for the neutralization reaction between sulfuric acid and sodium hydroxide.

The balanced chemical equation for the neutralization reaction is: H2SO4 + 2NaOH → Na2SO4 + 2H2O

From the equation, we can see that 1 mole of sulfuric acid (H2SO4) reacts with 2 moles of sodium hydroxide (NaOH).

Using the molar mass of sulfuric acid (H2SO4) and sodium hydroxide (NaOH), we can calculate the amount of each substance needed to neutralize the other.

The molar mass of H2SO4 is approximately 98.08 g/mol, and the molar mass of NaOH is approximately 40.00 g/mol.

Now, let's calculate the amount of sulfuric acid needed to neutralize 80g of sodium hydroxide.

Step 1: Calculate the moles of NaOH Using the molar mass of NaOH: Moles of NaOH = Mass of NaOH / Molar mass of NaOH Moles of NaOH = 80g / 40.00 g/mol Moles of NaOH = 2 moles

Step 2: Calculate the moles of H2SO4 From the balanced chemical equation, we know that 1 mole of H2SO4 reacts with 2 moles of NaOH. So, moles of H2SO4 = 1/2 * Moles of NaOH Moles of H2SO4 = 1/2 * 2 Moles of H2SO4 = 1 mole

Step 3: Calculate the mass of 100% H2SO4 needed Now, we need to calculate the mass of 100% H2SO4 needed, which is equivalent to the mass of the 40% solution.

Mass of 100% H2SO4 = Moles of H2SO4 * Molar mass of H2SO4 Mass of 100% H2SO4 = 1 mole * 98.08 g/mol Mass of 100% H2SO4 = 98.08g

Step 4: Calculate the mass of 40% H2SO4 solution needed The mass of the 40% H2SO4 solution can be calculated using the formula: Mass of 40% H2SO4 solution = (Mass of 100% H2SO4 / % purity of H2SO4 in the solution) * 100 Mass of 40% H2SO4 solution = (98.08g / 40%) * 100 Mass of 40% H2SO4 solution = 245.2g

Answer: The mass of the 40% sulfuric acid solution needed to neutralize 80g of sodium hydroxide is approximately 245.2 grams.