Question

Какая масса железа прореагирует без остатка с 4 г серы, если они соединяются в отношении масс 7:4? Точность вычислений — до десятых.

Answer 1

Ответ:

Здесь решается пропорцией, пусть масса железа х, тогда х/7=4/4, из этого следует что 7 грамм.

Answer 2

Calculating the Mass of Iron Reacting with Sulfur

To calculate the mass of iron that will react completely with 4g of sulfur, given that they combine in a ratio of 7:4, we can use the concept of the mole ratio in chemical reactions.

Step 1: Calculate the Molar Mass of Iron and Sulfur

The molar mass of iron (Fe) is approximately 55.85 g/mol, and the molar mass of sulfur (S) is approximately 32.07 g/mol.

Step 2: Determine the Mole Ratio

The given ratio of masses (7:4) can be converted to a mole ratio by dividing each mass by its molar mass. This gives us a mole ratio of approximately 7:1.25 for iron and sulfur, respectively.

Step 3: Calculate the Amount of Substance

We can use the mole ratio to find the amount of substance of sulfur and then use it to find the amount of substance of iron.

Step 4: Calculate the Mass of Iron

Using the amount of substance of iron, we can calculate the mass of iron that will react completely with 4g of sulfur.

Calculation

Given: - Mass of sulfur (S): 4g - Molar mass of iron (Fe): 55.85 g/mol - Molar mass of sulfur (S): 32.07 g/mol

1. Calculate the amount of substance of sulfur: - Amount of substance of sulfur = Mass of sulfur / Molar mass of sulfur - Amount of substance of sulfur = 4g / 32.07 g/mol - Amount of substance of sulfur ≈ 0.1247 moles

2. Calculate the amount of substance of iron using the mole ratio: - Amount of substance of iron = (7/1.25) * Amount of substance of sulfur - Amount of substance of iron ≈ 6.24 moles

3. Calculate the mass of iron: - Mass of iron = Amount of substance of iron * Molar mass of iron - Mass of iron ≈ 6.24 moles * 55.85 g/mol - Mass of iron ≈ 348.14g

Therefore, approximately 348.14 grams of iron will react completely with 4 grams of sulfur, given that they combine in a ratio of masses of 7:4.