
Вычислить массу бромида калия, который образуется в реакции между 12 г калия и бромом


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Calculating the Mass of Potassium Bromide
To calculate the mass of potassium bromide formed in the reaction between 12 g of potassium and bromine, we can use the balanced chemical equation for the reaction between potassium and bromine to form potassium bromide.
The balanced chemical equation for the reaction is: 2K + Br2 → 2KBr
From the balanced chemical equation, we can see that 2 moles of potassium react with 1 mole of bromine to produce 2 moles of potassium bromide.
Steps to Calculate the Mass of Potassium Bromide:
1. Calculate the Moles of Potassium: Using the given mass of potassium (12 g) and the molar mass of potassium (39.10 g/mol), we can calculate the moles of potassium.
Moles of potassium = Mass of potassium / Molar mass of potassium Moles of potassium = 12 g / 39.10 g/mol
Moles of potassium ≈ 0.307 moles
2. Use the Stoichiometry of the Reaction: From the balanced chemical equation, we know that 2 moles of potassium react with 1 mole of bromine to produce 2 moles of potassium bromide.
Moles of bromine = Moles of potassium / 2 Moles of bromine ≈ 0.307 moles / 2 Moles of bromine ≈ 0.154 moles
3. Calculate the Mass of Potassium Bromide: Now, we can use the moles of bromine to calculate the mass of potassium bromide formed.
Mass of potassium bromide = Moles of bromine × Molar mass of potassium bromide Molar mass of potassium bromide = Molar mass of potassium (K) + Molar mass of bromine (Br) Molar mass of potassium bromide = 39.10 g/mol (K) + 79.90 g/mol (Br) Molar mass of potassium bromide ≈ 119.00 g/mol
Mass of potassium bromide ≈ 0.154 moles × 119.00 g/mol Mass of potassium bromide ≈ 18.23 g
The mass of potassium bromide formed in the reaction is approximately 18.23 grams.


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