Question

Составьте реакции в моллекулярных и ионных формах: H2SO4+Zn CuO+H2SO4 Пожалуйста полностью

Answer 1

Ответ:

Цинк с разбавленной:

$H_2SO_4+Zn=ZnSO_4+H_2 \uparrow\\2H^++SO_4^{2-}+Zn=Zn^{2+}+SO_4^{2-}+H_2 \uparrow\\2H^++Zn=Zn^{2+}+H_2 \uparrow$

Цинк с концентрированной:

$5H_2SO_4+4Zn=4ZnSO_4+H_2S \uparrow +4H_2O\\10H^++5SO_4^{2-}+4Zn=4Zn^{2+}+4SO_4^{2-}+H_2S \uparrow + 4H_2O\\10H^++SO_4^{2-}+4Zn=4Zn^{2+}+H_2S \uparrow+4H_2O$

Оксид меди (II) с серной кислотой:
$CuO+H_2SO_4=CuSO_4+H_2O\\CuO+2H^++SO_4^{2-}=Cu^{2+}+SO_4^{2-}+H_2O\\CuO+2H^+=Cu^{2+}+H_2O$

Answer 2

Molecular and Ionic Reactions

Let's break down the reactions for each compound:

1. H2SO4: - In molecular form: H2SO4 - In ionic form: 2H^+ + SO4^2-

2. Zn: - In molecular form: Zn - In ionic form: Zn^2+

3. CuO: - In molecular form: CuO - In ionic form: Cu^2+ + O^2-

Reactions:

1. H2SO4 + Zn: - Molecular form: H2SO4 + Zn - Ionic form: 2H^+ + SO4^2- + Zn^2+ -> ZnSO4 + H2

2. H2SO4 + CuO: - Molecular form: H2SO4 + CuO - Ionic form: 2H^+ + SO4^2- + Cu^2+ + O^2- -> CuSO4 + H2O

These reactions involve the dissociation of the compounds into their respective ions and the subsequent formation of new compounds based on the combination of these ions.

I hope this helps! If you have further questions or need additional information, feel free to ask.