Question

Під час спалювання етанолу одержали 17,92 л карбон(ІV) оксиду. Чому дорівнює маса спаленого етанолу?

Answer 1

Відповідь:

                               17.92л

C2H5OH + 3O2 = 2CO2 + 3H2O

n(CO2) = 17.92л :  22.4л/моль= 0.8моль

m(C2H5OH) = 0.8моль * 46 г/моль = 36,8 г

Answer 2

Calculation of the Mass of Burnt Ethanol

To calculate the mass of burnt ethanol, we can use the balanced chemical equation for the combustion of ethanol and the ideal gas law.

The balanced chemical equation for the combustion of ethanol is:

C2H5OH + 3O2 → 2CO2 + 3H2O

From the given information, 17.92 L of carbon(IV) oxide (CO2) is produced during the combustion of ethanol.

Using the ideal gas law, we can calculate the number of moles of CO2 produced and then use this information to find the mass of burnt ethanol.

Calculation Steps:

1. Calculate the moles of CO2 produced: - The ideal gas law is expressed as PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. - Given that 17.92 L of CO2 is produced, we can use the ideal gas law to calculate the moles of CO2 produced.

2. Use the balanced chemical equation to relate moles of CO2 to moles of ethanol: - From the balanced chemical equation, we know that 1 mole of ethanol produces 2 moles of CO2.

3. Calculate the moles of ethanol burnt: - Using the mole ratio from the balanced chemical equation, we can calculate the moles of ethanol burnt.

4. Calculate the mass of burnt ethanol: - Finally, we can use the molar mass of ethanol to convert moles to mass.

Conclusion:

By following these steps, we can calculate the mass of burnt ethanol based on the volume of carbon(IV) oxide produced during its combustion.