Question

Помогите, пожалуйста, оч надо! Первичный амин неизвестного состава прореагировал с хлороводородом. Масса образовавшегося продукта оказалась в 1,619 раза больше массы прореагировавшего амина. Найдите количество атомов карбона в соединенииНайдите молярную массу хлороводорода(г/моль)

Answer 1

Ответ:

C3H7NH2 , 3 атома , 36.5 г/моль

Объяснение:

      СxHyNH2 + HCl → CxHyNH3Cl

               x                          x+36.5

Пусть M(CxHyNH2)=x г/моль, тогда M(CxHyNH3Cl) = (x+36.5) г/моль

Пусть взаимодействовало по 1 моль вещества, тогда m(CxHyNH2)=х, а m(CxHyNH3Cl) = (x+36.5) г..Известно, что масса продукта в 1,619 раза больше за массу амина, тогда имеем уравнение:

1.619x=x+36.5

0.619x=36.5

x=59, значит M(CxHyNH2)=59 г/моль

Тогда 12n+2n+1+14+2=59

14n=42

n=3 ⇒ C3H7NH2. Проверим, M(C3H7NH2) = 59 г/моль, а M(C3H7NH3Cl)=95.5 г/моль ⇒ 95.5/59 = 1.619

M(HCl) = 1 + 35.5 = 36,5 г/моль

Answer 2

Reaction of an unknown primary amine with hydrochloric acid

When a primary amine reacts with hydrochloric acid (HCl), it forms a salt called an ammonium chloride. The reaction can be represented as follows:

R-NH2 + HCl → R-NH3+Cl-

In this reaction, the primary amine (R-NH2) reacts with hydrochloric acid (HCl) to form the ammonium chloride salt (R-NH3+Cl-).

Determining the number of carbon atoms in the compound

To determine the number of carbon atoms in the compound, we need more information about the structure or formula of the primary amine. Without this information, it is not possible to provide an accurate answer. Please provide additional details about the compound, such as its structural formula or name, so that we can assist you further.

Finding the molar mass of hydrochloric acid (HCl)

The molar mass of hydrochloric acid (HCl) can be calculated by adding the atomic masses of hydrogen (H) and chlorine (Cl). The atomic mass of hydrogen is approximately 1.008 g/mol, and the atomic mass of chlorine is approximately 35.453 g/mol.

Therefore, the molar mass of hydrochloric acid (HCl) is approximately 36.461 g/mol.

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