Question

Продолжите логическую цепочку и объясните: 1. NaCl-->NaOH-->Na20-->...2. K2SO4-->H2SO4-->SO3-->...(Дам 65 баллов)​

Answer 1

Ответ: 1) NaCI + H20 = NaOH + HCI

2Na + NaOH -> Na2O + NaH

2Na2O + 2SO4 -> 2Na2SO4 + O2

2) не поняла

Объяснение:

Answer 2

1. NaCl --(electrolysis)--> NaOH --(dehydration)--> Na2O --(reacts with water)--> Na2O·H2O --(further dehydration)--> Na2O2

In this logical chain, we start with sodium chloride (NaCl) and perform electrolysis, which breaks it down into sodium hydroxide (NaOH). Then, through a process of dehydration, we obtain sodium oxide (Na2O). When Na2O reacts with water, it forms sodium hydroxide again, but in a hydrated form: Na2O·H2O. By further dehydration, we finally arrive at sodium peroxide (Na2O2).

2. K2SO4 --(heating)--> K2S2O7 --(heating)--> K2SO4 + SO3

For the given logical chain, we begin with potassium sulfate (K2SO4). When K2SO4 is heated, it decomposes to form potassium pyrosulfate (K2S2O7). If we continue heating K2S2O7, it decomposes back into potassium sulfate and sulfur trioxide (SO3). Therefore, the final product in this chain is potassium sulfate (K2SO4) and sulfur trioxide (SO3).

Note: The process of obtaining the final products in these logical chains may involve multiple steps and conditions. The examples provided represent simplified versions of the reactions for the sake of illustration.