Question

CuSO4>Cu(OH)2>CuO>CuCl2​

Answer 1

Ответ:

CuSO4+ 2NaOH⇒Cu(OH)2↓ +Na2SO4

Cu(OH)2⇒CuO +H2O

CuO +2HCl⇒CuCl2 +H2

Answer 2

The statement "CuSO4 > Cu(OH)2 > CuO > CuCl2" implies a ranking of copper compounds based on their solubility in water. In this case, the ">" symbol represents "greater than" and indicates that a compound on the left is more soluble than the one on the right.

Let's break down the comparison:

1. CuSO4 (copper(II) sulfate): Copper sulfate is a highly soluble compound in water. It dissociates into copper ions (Cu²⁺) and sulfate ions (SO₄²⁻). Therefore, CuSO4 is more soluble than all the other compounds mentioned in the statement.

2. Cu(OH)2 (copper(II) hydroxide): Copper hydroxide is moderately soluble in water. It does undergo some dissociation, releasing copper ions (Cu²⁺) and hydroxide ions (OH⁻), but the solubility is lower than that of copper sulfate. So, Cu(OH)2 is less soluble than CuSO4 but more soluble than the next two compounds.

3. CuO (copper(II) oxide): Copper oxide is less soluble in water compared to both copper sulfate and copper hydroxide. It reacts with water to a limited extent, forming copper hydroxide. However, the solubility of CuO is lower than that of Cu(OH)2.

4. CuCl2 (copper(II) chloride): Copper chloride is the least soluble among the mentioned compounds. It dissolves to a limited extent, releasing copper ions (Cu²⁺) and chloride ions (Cl⁻). CuCl2 is less soluble than all the other compounds in the statement.

To summarize the solubility rankings based on the given statement:

CuSO4 > Cu(OH)2 > CuO > CuCl2