Question

7.44 г оксида 1 валентного Me образует 17.04 г сульфата. Me - ?

Answer 1

Me₂O + H₂SO₄ → Me₂SO₄ + H₂O

νMe₂O = mMe₂O / μMe₂O
νMe₂SO₄ = mMe₂SO₄ / μMe₂SO₄
νMe₂O = νMe₂SO₄ из уравнения реакции

mMe₂O / μMe₂O = mMe₂SO₄ / μMe₂SO₄

7.44 / (2μMe+16) = 17.04 / (2μMe + 32 + 64)
14.88μMe + 714.24 = 34.08μMe + 272.64
19.2μMe = 441.6
μMe = 23
Me = Na

Answer 2

To find the value of Me, we need to set up an equation using the given information. Let's denote Me as the chemical symbol for the metal.

The molar mass of the oxide (MeO) can be calculated by adding the atomic mass of Me (M) and the atomic mass of oxygen (O). The molar mass of sulfate (MeSO4) can be calculated by adding the atomic mass of Me, sulfur (S), and four oxygen atoms.

From the given information:

Mass of MeO = 7.44 g Mass of MeSO4 = 17.04 g

Let's assume the molar mass of Me is x g/mol.

The equation can be set up as follows:

(M + 16) g/mol + 32 g/mol = (x + 32 + 4 × 16) g/mol

We can simplify this equation:

M + 16 + 32 = x + 32 + 64 M + 48 = x + 96

Now, we can solve for Me (M) by rearranging the equation:

M = x + 96 - 48 M = x + 48

Therefore, the value of Me is x + 48.

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