Question

(8-t)^2-t(t+7), при t= -3/23

Answer 1

(8-t)² -t(t+7)=64-16t+t²-t²-7t=64-23t,
если t=  $- \frac{3}{23}$, то  $64-23*(- \frac{3}{23} )=64+3=67.$

Answer 2

To evaluate the expression (8-t)^2 - t(t+7) at t = -3/23, we can substitute the given value of t into the expression and simplify it.

Let's substitute t = -3/23 into the expression:

(8 - (-3/23))^2 - (-3/23)((-3/23) + 7)

Simplifying the expression step by step:

(8 + 3/23)^2 - (-3/23)(7/23)

Now, let's simplify further:

(184/23)^2 - (-21/529)

To square a fraction, we square the numerator and the denominator separately:

(184^2/23^2) - (-21/529)

Calculating the square of the numerator:

(33856/529) - (-21/529)

Now, we can subtract the fractions:

(33856/529) + (21/529)

Adding the fractions:

(33856 + 21)/529

Simplifying the numerator:

33877/529

Therefore, the value of the expression (8-t)^2 - t(t+7) at t = -3/23 is 33877/529.