Вопрос задан 03.09.2020 в 18:36. Предмет Математика. Спрашивает Гончар Соня.

В ДЕТСКИЙ САД ПРИВЕЗЛИ 3 ЯЩИКА ФРУКТОВ ПО 8 КГ В КАЖДОМ. Часть фруктов съели, и тогда осталось 15

кг. Сколько фруктов съели за завтраком? нужно решить задачу и составить все обратные задачи и сделать краткую запись любым способом.
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Problem Analysis

To solve this problem, we need to determine how many fruits were eaten for breakfast. We know that 3 boxes of fruits were brought to the kindergarten, each weighing 8 kg. After some fruits were eaten, there were 15 kg left. We need to find the weight of the fruits that were eaten.

Solution

Let's calculate the total weight of the fruits brought to the kindergarten: - 3 boxes * 8 kg/box = 24 kg

We know that after breakfast, there were 15 kg of fruits left. Therefore, the weight of the fruits eaten for breakfast is: - Total weight - Weight left = 24 kg - 15 kg = 9 kg

So, 9 kg of fruits were eaten for breakfast.

Reverse Problem

To create a reverse problem, we can change the values in the original problem and ask a similar question. For example:

Reverse Problem 1: In a kindergarten, 4 boxes of fruits were brought, each weighing 6 kg. After breakfast, there were 18 kg of fruits left. How many kilograms of fruits were eaten for breakfast?

Solution: - Total weight = 4 boxes * 6 kg/box = 24 kg - Weight left = 18 kg - Weight eaten = Total weight - Weight left = 24 kg - 18 kg = 6 kg

Therefore, 6 kg of fruits were eaten for breakfast.

Reverse Problem 2: In a kindergarten, 2 boxes of fruits were brought, each weighing 10 kg. After breakfast, there were 16 kg of fruits left. How many kilograms of fruits were eaten for breakfast?

Solution: - Total weight = 2 boxes * 10 kg/box = 20 kg - Weight left = 16 kg - Weight eaten = Total weight - Weight left = 20 kg - 16 kg = 4 kg

Therefore, 4 kg of fruits were eaten for breakfast.

These are two examples of reverse problems that can be created based on the original problem.

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