Question

На складе имеются гироскутеры и сигвеи. Количество гироскутеров относится к количеству сигвеев как 3:4. Какое наибольшее количество гироскутеров может быть на складе , если общее количество гироскутеров и сигвеев на складе не больше чем 45.

Answer 1

3+4=7 ⇒
общее количество гироскутеров и сигвеев кратно 7
наибольшее число кратное 7 и не большее 45 это 42
гироскутеров 3/7 
42*3/7=18

проверка
сигвеев 42*4/7=24
18+24=42

 

Answer 2

Understanding the Problem

To find the maximum number of hoverboards that can be on the warehouse, given that the total number of hoverboards and segways is no more than 45, we need to determine the relationship between the quantities of hoverboards and segways.

Analyzing the Given Information

The problem states that the ratio of hoverboards to segways is 3:4. This means that for every 3 hoverboards, there are 4 segways. Additionally, the total number of hoverboards and segways on the warehouse is no more than 45.

Solving the Problem

To find the maximum number of hoverboards, we can set up the following equation based on the given ratio:

Let x be the number of hoverboards. Let y be the number of segways.

According to the given ratio, we have the equation:

x/y = 3/4

To find the maximum number of hoverboards, we need to find the highest possible value of x that satisfies the equation and the condition that the total number of hoverboards and segways is no more than 45.

We can solve this problem by setting up a system of equations:

x/y = 3/4 (Equation 1) x + y ≤ 45 (Equation 2)

To solve this system of equations, we can use substitution or elimination.

Let's solve it using substitution:

From Equation 1, we can express x in terms of y:

x = (3/4)y

Substituting this into Equation 2:

(3/4)y + y ≤ 45

Simplifying:

(7/4)y ≤ 45

Multiplying both sides by 4/7:

y ≤ (45 * 4/7)

Simplifying:

y ≤ 25.71

Since the number of segways must be a whole number, the maximum number of segways is 25.

Substituting this value back into Equation 1:

x/25 = 3/4

Cross-multiplying:

4x = 25 * 3

Simplifying:

4x = 75

Dividing both sides by 4:

x = 18.75

Since the number of hoverboards must be a whole number, the maximum number of hoverboards is 18.

Answer

Therefore, the maximum number of hoverboards that can be on the warehouse is 18 if the total number of hoverboards and segways on the warehouse is no more than 45.