
Выразите переменую у через переменую х и найдите два каких нибудь решения уравнения1/3
х+у-1=01,4х+у-2=0Найдите значение у если уравнение 7х+2у=14 Пр0шу помогите!!!!!!!

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И так далее и тому подобное



Solving the Equations
To solve the given system of equations, let's express variable "у" in terms of variable "х" in the first equation and substitute it into the second equation. Then we can solve for "х" and find the corresponding values of "у".
The given equations are:
1) (1/3)ху - 1 = 0 2) 1.4х + у - 2 = 0
Let's solve the equations step by step.
Step 1: Expressing у in terms of х
From the first equation, we can express "у" in terms of "х" as follows:
(1/3)ху - 1 = 0
Adding 1 to both sides:
(1/3)ху = 1
Multiplying both sides by 3:
ху = 3
Dividing both sides by "х":
у = 3/х
Step 2: Substituting the expression for у into the second equation
Now, let's substitute the expression for "у" into the second equation:
1.4х + у - 2 = 0
Substituting "у = 3/х":
1.4х + (3/х) - 2 = 0
Step 3: Solving for х
To solve for "х", we can multiply the entire equation by "х" to eliminate the denominator:
1.4х² + 3 - 2х = 0
Rearranging the terms:
1.4х² - 2х + 3 = 0
Now, we can solve this quadratic equation using the quadratic formula:
х = (-b ± √(b² - 4ac)) / (2a)
For our equation, a = 1.4, b = -2, and c = 3. Substituting these values into the quadratic formula:
х = (-(-2) ± √((-2)² - 4(1.4)(3))) / (2(1.4))
Simplifying:
х = (2 ± √(4 - 16.8)) / 2.8
х = (2 ± √(-12.8)) / 2.8
Since the discriminant (√(-12.8)) is negative, the quadratic equation has no real solutions. Therefore, there are no real values of "х" that satisfy the given system of equations.
Finding the Value of у for the Equation 7х + 2у = 14
To find the value of "у" for the equation 7х + 2у = 14, we need to substitute a value of "х" into the equation and solve for "у".
Since we couldn't find any real solutions for "х" in the previous system of equations, we cannot find a specific value of "у" that satisfies the equation 7х + 2у = 14.
If you have any further questions, feel free to ask!


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