Question

Во сколько раз уменьшаемое больше числа 56, если вычитаемое больше разности в 7 раз и разность делится на 7?

Answer 1

56*7=392 392:7=56
Ответ: в о раз уменьшаемое больше чем 56

Answer 2

Problem Analysis

We are given the following conditions: - The subtracted number is greater than the difference by a factor of 7. - The difference is divisible by 7.

We need to find the ratio by which the subtracted number is greater than 56.

Solution

Let's assume the subtracted number is x. According to the given conditions, we have the following equations:

1. x - 56 = 7(x - (x - 56)) 2. x - 56 = 7(56)

Let's solve these equations step by step.

Equation 1

x - 56 = 7(x - (x - 56))

Simplifying the equation: x - 56 = 7(x - x + 56) x - 56 = 7(56)

Simplifying further: x - 56 = 7 * 56 x - 56 = 392

Adding 56 to both sides: x = 392 + 56 x = 448

Equation 2

x - 56 = 7(56)

Simplifying the equation: x - 56 = 7 * 56 x - 56 = 392

Adding 56 to both sides: x = 392 + 56 x = 448

Conclusion

The subtracted number x is equal to 448. Therefore, the subtracted number is 448/56 = 8 times greater than 56.

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