Question

Периметр прямокутника дорівнює 20см. знайдіть довжину прямокутника, якщо вона на 2 см більша за його ширину

Answer 1

Х-длина
х-2  -ширина

(X+X-2)*2=20
(2X-2)*2=20
4X-4=20
4X=20+4
4X=24
X=24/4
X=6

Answer 2

Calculation of the Length of a Rectangle

To find the length of a rectangle when its perimeter is 20 cm and it is 2 cm longer than its width, we can use the formula for the perimeter of a rectangle, which is given by:

Perimeter = 2 * (Length + Width)

Let's denote the width of the rectangle as w. According to the problem statement, the length of the rectangle is 2 cm longer than its width, so the length can be expressed as w + 2.

Substituting these values into the perimeter formula, we get:

20 = 2 * (w + (w + 2))

Simplifying the equation, we have:

20 = 2 * (2w + 2)

Now, we can solve for w:

20 = 4w + 4

4w = 20 - 4

4w = 16

w = 16 / 4

w = 4

Therefore, the width of the rectangle is 4 cm. Since the length is 2 cm longer than the width, the length of the rectangle is:

Length = Width + 2 = 4 + 2 = 6 cm

So, the length of the rectangle is 6 cm.