Question

Из аэродрома в 8 часов утра вылетели два самолета в противоположных направлениях. Скорость первого 620 км/ч. Через 11 часов расстояние между ними было 3540 км. Найдите скорость второго самолета.

Answer 1

1)620×3=1860
2)3540-1860=1680 (км)
Ответ:1680 км.

Answer 2

Такого не может быть, а если в 11 часов а не через то:

1) первый самолет пролетел 620*3= 1860 км

2) второй самолет пролетел 3540-1860 = 1680 км

3) скорость 2 самолета 1680:3 = 560 км/ч

Answer 3

Problem Analysis

We are given that two airplanes took off from an airport in opposite directions at 8:00 AM. The speed of the first airplane is 620 km/h. After 11 hours, the distance between the two airplanes is 3540 km. We need to find the speed of the second airplane.

Solution

Let's assume the speed of the second airplane is x km/h.

The first airplane travels for 11 hours at a speed of 620 km/h, so the distance it covers is:

Distance of the first airplane = Speed of the first airplane × Time = 620 km/h × 11 h = 6820 km.

The second airplane also travels for 11 hours, so the distance it covers is:

Distance of the second airplane = Speed of the second airplane × Time = x km/h × 11 h = 11x km.

The total distance between the two airplanes after 11 hours is given as 3540 km. Therefore, we can write the equation:

Distance of the first airplane + Distance of the second airplane = Total distance

Substituting the values we have:

6820 km + 11x km = 3540 km

Simplifying the equation:

11x km = 3540 km - 6820 km

11x km = -3280 km

Dividing both sides of the equation by 11:

x km = -3280 km / 11

x km ≈ -298.18 km/h

Since speed cannot be negative, we can conclude that the second airplane's speed is approximately 298.18 km/h.

Answer

The speed of the second airplane is approximately 298.18 km/h.

Explanation

The first airplane travels at a speed of 620 km/h for 11 hours, covering a distance of 6820 km. The second airplane's speed is represented by x km/h, and it also travels for 11 hours. The total distance between the two airplanes after 11 hours is given as 3540 km. By solving the equation, we find that the speed of the second airplane is approximately 298.18 km/h.